The applicable decay formula is:N = No*e^(-kt)WhereN = Mass left after time tNo = Original massk = constantt = half lifeUsing the values given,N/No = e^(-0.1446t) = 1/2ln (1/2) = -0.1446 t *ln e^1-0.6931 = -0.1446 tt = 0.6331/0.1446 = 4.79 daysTherefore, half-life is 4.8 days.

3 0

3 years ago

Read 2 more answers

Let f: 4 → and c(t): → 4. suppose ∇f(1, 1, π, e6) = (0, 1, 2, −4), c(π) = (1, 1, π, e6), and c'(π) = (13, 12, 0, 1). find d(f ∘

Tems11 [23]

3tt hope it helps just starting out

6 0

3 years ago

there are 30 students in a math class of the 30 students 30% have an a in math 40% have a b in math how many students have a c i

stepladder [879]

the answer is 9

30 percent of 30 is 9