<span><span>12</span> + <span>15</span> + <span>45</span> + 1 <span>23</span> = <span>196</span> = 3<span>16</span> ≅ 3.166667</span>
120º is 1/3 of a complete revolution of 360º. So the area of this sector should be 1/3 the area of the complete circle.
A circle with radius 9 has area 9^2 π = 81π.
So the sector has area 81π/3.
Put another way: The area <em>A</em> of a circular sector and its central angle <em>θ</em> (in degrees) occur in the same ratio as the area of the entire circle with radius <em>r</em> according to
<em>A</em> / <em>θ </em>º = (π <em>r </em>^2) / 360º
==> <em>A</em> = π/360 <em>θ r</em> ^2
In this case, <em>r</em> = 9 and <em>θ</em> = 120º, so
<em>A</em> = π/360 * 120 * 81 = 81π/3
Step-by-step explanation:
From the given table it is obvious that 162 is the largest number of the given numbers which corresponds to 45° angle.
So, he should kick the football at 45° angle for maximum distance.
X² - 15 x + 36 = 0
x² - 12x - 3x + 36 = 0
x( x - 12) - 3( x - 12) = 0
(x - 3)( x - 12) = 0
x - 3 = 0
x = 3
or
x - 12 = 0
x = 12
The solutions are 3 and 12
