The sample space is nothing but ALL possible outcomes. In this case you have Black & Red id's. Then the sample space is {black, red}

we know that, the mixture amount is the sum of 11 + p, or
11 + p = m.
we also know that, the total value is also a sum of
25.3 + 4.5p = 3.29m.
Well, the first one is 2/40=1/20. The 2nd one is 1/39. You multiply these to get 1/780.
Answer 16
36/2.25= 16 pieces of rope
Here, x-coordinate = 2
y - coordinate = 3
It would be: 2x + 3y ≥ 6
In short, Your Answer would be Option C
Hope this helps!