Distance of armadillo = V * t = 3t
Distance of racoon = V * (t-2) =5*(t-2)
Distance of armadillo + distance of racoon = 38
3t + 5(t-2)=38
3t + t5 - 10 =38
8t=48
t=6
The anwser is: they will be 38 km apart after 6 hours, so it is 6p.m (12a.m+6 hours)
Answer:
42
Step-by-step explanation:
(30+54)/2 = 42
30+54 = 84
84/2 = 42
We can drop a perpendicular from X to PQ at A, and from Y to RS at B. Then XA = YB = 48/10 = 24/5. We can also draw a line through X parallel to BY meeting the line through Y parallel to RS at C.
Then XC = 24/5 + 24/5 + 10 = 98/5 and YC = 10 - 34/5 = 16/5, so XY^2 = XC^2 + YC^2 = (98/5)^2 + (16/5)^2 = 1972/5.
Answer:
Aubrey ran 3 1/3 miles further than what she walked.
Step-by-step explanation:
This would be your basic subtraction problem. So, 13 1/6 - 9 5/6.
Since you can't subtract 5/6 from 1/6, let's borrow from 13. Now, instead of 13, it would be 12. Adding the whole (1) or 6/6 to the 1/6, you'll get 7/6. Now you can subtract. 7/6 - 5/6 = 2/6. Moving on, 12 - 9 = 3.
Therefore, your answer is 3 2/6. In simplified terms, it would be 3 1/3.