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timurjin [86]
3 years ago
13

Q: At noon the armadillo left the wild kingdom and headed north at 3 kilometers per hour . two hours later the raccoon left the

same kingdom and headed south at 5 kilometers per hour . at what time will the animalse be 38 kilometera apart ?
Mathematics
1 answer:
Ghella [55]3 years ago
5 0
Distance of armadillo = V * t = 3t
Distance of racoon = V * (t-2) =5*(t-2)
Distance of armadillo + distance of racoon = 38
3t + 5(t-2)=38
3t + t5 - 10 =38
8t=48
t=6
The anwser is: they will be 38 km apart after 6 hours, so it is 6p.m (12a.m+6 hours) 
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