Ask question

Ask question

All categories

3 years ago

15

Line segment AB has endpoints A(1, 2) ) and B(5,3) Find the coordinates of the point that divides the line segment directed from

A to B in the ratio of 13.

1 answer:

saw5 [17]3 years ago

6 0

Answer:

try Jiskha Homework Help

Step-by-step explanation:

You might be interested in

What does x equal in this equation: 24+3x=3x+3(7-1) Please help this is due tomorrow!

Zinaida [17]

      24 + 3x = 3x + 3(7 - 1)

Eliminate the parentheses: 24 + 3x = 3x + 3(6)

      24 + 3x = 3x + 18

Subtract 3x from each side:    <em>24 = 18</em>

Look at that for a second. Can ANY value of 'x' make 24 equal to 18 ?
I don't think so.
There's NO number that makes the equation a true statement.

That's just another way to say: "The equation has NO solution."

3 0

2 years ago

10x+20=7x-8<br><br> Solve for x.

Kazeer [188]

Step-by-step explanation:

Isolate the variable

10x - 7x = -20 - 8

3x = -28

x = -9.333333333333

5 0

2 years ago

Write the algebraic expression described. Recall that two angles are supplementary if their sum is 180 degrees. If one angle mea

Alina [70]

If one angle is d° then it's supplement is
(180-d)°

8 0

3 years ago

Write the standard form of the equation of the parabola with the given focus or directrix and

horsena [70]

Answer:

x = 1/20 y^2

Step-by-step explanation:

This is a rightward opening (sideways ) parabola

Directrix = x = -5

Distance formula form point x,y to directrix and focus are equal:

(x - -5)^2 = (x-5)^2 + y^2

x^2 + 10x + 25 = x^2 - 10x + 25 + y^2

20x = y^2

x = 1/20 y^2

3 0

1 year ago

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago