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rosijanka [135]
3 years ago
9

A genetic trait is inherited via the Y chromosome such that for a father with the trait, his male offspring have a 25% chance of

inheriting it but his female offspring cannot inherit it. Suppose that in a certain population, 40% of offspring are male and offspring genders are independent events. For a father with the trait who has two offspring, what is the probability that the older offspring has the trait and the younger offspring does not?
Biology
1 answer:
Maru [420]3 years ago
5 0

Answer:

0.09

Explanation:

let us define these events as

O = older

Y = younger

Prob(O) = 40% offspring x 25% chance of inheritance

= 0.4x0.25

= 0.1

P(Y') = 40% offspring x (1-25%) +(1-40%)x1

= 0.4x0.75 + 0.6x1

= 0.3+0.6

= 0.9 this is the probability of having the trait.

Probability that older offspring has trait but younger does not have it

Prob(O n Y') = prob(O) x Prob(Y')

= 0.1x0.9

= 0.09

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Dihybrid Cross

Parental)   WwYy      x      WwYy

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Punnet Square)

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               WY     WWYY   WWYy   WwYY  WwYy

               Wy      WWYy   WWyy    WwYy  Wwyy

               wY      WwYY   WwYy    wwYY  wwYy

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White phenotype: 12/16 = 120 individuals

Yellow phenotype: 3/16 = 30 individuals

Green Phenotype: 1/16 = 10 individuals

To know how many offspring are expected to have the white, yellow, and green phenotypes, you can perform a three simple rule. This is:

16 ------- 160 offspring

12 White ------- X = 120 offspring

3 Yellow ------- X= 30 offspring

1 Green --------X = 10 offspring              

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