Welcome to the era of LeBron. If you thought he was doing the game a disservice by being a sore loser and egomaniac, you haven’t seen anything yet. It wasn’t enough that he decided to become a pariah, he and his group of cronies have decided they want to ruin the NBA.
How? By systematically turning every superstar in the NBA into LeBron James. They are trying to turn them into spoiled, delusional, lying, quitting cowards.
Two of the biggest stories this offseason have been the drama in Denver and New Orleans. Both players, for whatever reasons, have decided that they no longer want to be the cornerstone of a franchise. Before the summer of Lebron, neither had really been asking to get out of their situations. So what is the common thread here? Well, both are represented by agent Leon Rose. Who else is represented by Rose? Why Mr. James, of course.
Answer:
See attachment.
Step-by-step explanation:
We want to graph the linear inequality y<2
We first of all graph the corresponding linear equation y=2 with a dashed line because all points on this line do not satisfy the inequality.
We then shade below the line y=2, to show that all points below the boundary line are solution to the inequality y<2
Hi there what you need is lagrange multipliers for constrained minimisation. It works like this,
V(X)=α2σ2X¯1+β2\sigma2X¯2
Now we want to minimise this subject to α+β=1 or α−β−1=0.
We proceed by writing a function of alpha and beta (the paramters you want to change to minimse the variance of X, but we also introduce another parameter that multiplies the sum to zero constraint. Thus we want to minimise
f(α,β,λ)=α2σ2X¯1+β2σ2X¯2+λ(\alpha−β−1).
We partially differentiate this function w.r.t each parameter and set each partial derivative equal to zero. This gives;
∂f∂α=2ασ2X¯1+λ=0
∂f∂β=2βσ2X¯2+λ=0
∂f∂λ=α+β−1=0
Setting the first two partial derivatives equal we get
α=βσ2X¯2σ2X¯1
Substituting 1−α into this expression for beta and re-arranging for alpha gives the result for alpha. Repeating the same steps but isolating beta gives the beta result.
Lagrange multipliers and constrained minimisation crop up often in stats problems. I hope this helps!And gosh that was a lot to type!xd
Dismiss the decimals as if they were not there. Then you multiple like a read number and write the answer. Adding the demcials back after you gort the answer
