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faust18 [17]
3 years ago
15

Two surveys were independently conducted to estimate a population mean, μ. denote the estimates and their standard errors by x1

and x2 and σx1 and σx2 . assume that x1 and x2 are unbiased. for some α and β, the two estimates can be combined to give a better estimator:
Mathematics
1 answer:
lyudmila [28]3 years ago
3 0

Hi there what you need is lagrange multipliers for constrained minimisation. It works like this,

V(X)=α2σ2X¯1+β2\sigma2X¯2

Now we want to minimise this subject to α+β=1 or α−β−1=0.

We proceed by writing a function of alpha and beta (the paramters you want to change to minimse the variance of X, but we also introduce another parameter that multiplies the sum to zero constraint. Thus we want to minimise

f(α,β,λ)=α2σ2X¯1+β2σ2X¯2+λ(\alpha−β−1).

We partially differentiate this function w.r.t each parameter and set each partial derivative equal to zero. This gives;

∂f∂α=2ασ2X¯1+λ=0

∂f∂β=2βσ2X¯2+λ=0

∂f∂λ=α+β−1=0

Setting the first two partial derivatives equal we get

α=βσ2X¯2σ2X¯1

Substituting 1−α into this expression for beta and re-arranging for alpha gives the result for alpha. Repeating the same steps but isolating beta gives the beta result.

Lagrange multipliers and constrained minimisation crop up often in stats problems. I hope this helps!And gosh that was a lot to type!xd

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Plsss help !!
Gennadij [26K]

Answer:

carnation $2.50; rose $3.00

Step-by-step explanation:

Let c = price of 1 carnation.

Let r = price of 1 rose.

3c + 5r = 22.5

3c + 2r = 13.50

Subtract the se3cond equation from the first equation.

3r = 9

r = 3

Now substitute r = 3 in the first equation and solve for c.

3c + 5r = 22.5

3c + 5(3) = 22.5

3c = 7.5

c = 2.5

Answer: carnation $2.50; rose $3.00

5 0
3 years ago
What is the length of the radius? startfraction 6 over 85 endfraction startfraction 85 over 12 endfraction startfraction 121 ove
melomori [17]

The length of the radius will be 22 units.

<h3>What is the radius?</h3>

The radius of a circle is defined as the distance of the center of the circle to its outer layer. It is a locus of a point present at some distance from the center point.

Now from the question, we have an expression:

r=(\dfrac{6}{85} )\times(\dfrac{85}{12} )\times (\dfrac{121}{36} )\times (\dfrac{157}{12} )

By solving the above equation we get

r=(\dfrac{18997}{864} )

r=22

Hence the length of the radius will be 22 units.

To know more about radius follow

brainly.com/question/24375372

6 0
2 years ago
Read 2 more answers
Please help!!!!!
Burka [1]

Answer:The answer is B

Step-by-step explanation: because mitchells line is traveling steeper than matthews

6 0
3 years ago
If VX = WZ = 40 cm and m∠ZVX = m∠XWZ = 22°, can ΔVZX and ΔWXZ be proven congruent by SAS? Why or why not?
Paul [167]

Answer: The ΔVZX and ΔWXZ are not congruent by SAS.

Explanation:

It is given that the VX = WZ = 40 cm and ∠ZVX = ∠XWZ = 22°.

Draw a figure as shown below,

According to the SAS rule of congruence, two triangles are congruent if two sides and their inclined angle is equal.

From the given figure it is easily noticed that in ΔVZX and ΔWXZ,

VX=WZ=40cm       (given)

\angle ZVX=\angle XWZ=22^{\circ}     (given)

XZ=XZ      (common side)

Since we have two sides and one angle is same. but we can not conclude that the ΔVZX and ΔWXZ are congruent by SAS, because the given angle is not the inclined angle of both equal sides.

Therefore, the  ΔVZX and ΔWXZ are not congruent by SAS.

4 0
3 years ago
Read 2 more answers
Evaluate function at the given value using the remainder theorem.
garik1379 [7]

Answer:

6

Step-by-step explanation:

f(a)=a^4-2a^3 -10a^2 -7a \\\\f(-2) = (-2)^4-2(-2)^3 -10(-2)^2 -7(-2)\\\\~~~~~~~~~=16-2(-8)-10(4)+14\\\\~~~~~~~~~=30+16-40\\\\~~~~~~~~~=46-40\\\\~~~~~~~~~=6

5 0
2 years ago
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