Answer:
6 ft
Step-by-step explanation:
Given that:
Length of rectangular banner = 18 ft
Total trim of banner available = 48 ft
To find:
Possible widths of the banner = ?
Solution:
Maximum trim available of the banner around the entire border of the banner = 48 ft
i.e. we are given the total perimeter of the rectangular banner.
Formula for perimeter of a rectangle is given as:
Putting the values of perimeter and length to find the value of width.
So, width possible is <em>6ft.</em>
Answer:
528 cm²
Step-by-step explanation:
First I would calculate the area of the side rectangles:
20 x 9 = 180 cm²
There are two identical rectangles on both sides so i would x2
180 x 2 = 360 cm²
The area of the middle rectangle:
6 x 20 = 120 cm²
The area of the triangles:
Area of a triangle = (Base x Height)/2
8 x 6 = 48
48 ÷ 2 = 24
There are two identical triangles on the bottom and the top so x2
24 x 2 = 48
Now add all the values up:
360 + 120 + 48 = 528 cm²
I hope this helps!
Hey buddy I am here to help!
Yes these r similar!
Hope this helps!
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Answer:
graph them and then see if they intersect(but if you notice that the coordss of the second line are all smaller than the coords of the first line, meaning that they wont be touching at all)
Step-by-step explanation:
Group first 2 and group last 2 and find factors and undistribute
(4x^3+x^2)+(-8x-2)
(x^2)(4x+1)+(-2)(4x+1)
x^2(4x+1)-2(4x+1)
answer is first one
