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Andre45 [30]
3 years ago
12

A set of history exam scores are normally distributed with a mean of 83.2 points and a standard deviation

Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0

Answer: .3330

Step-by-step explanation:

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Please help asap!! Thank you
djyliett [7]

Step-by-step explanation:

Hey, there!!

Let's simply work with it,

60° + 2x° + (2x+12)° = 180° { being a linear pair}.

or, 72° + 4x = 180°

4x = 180° - 70°

x =  \frac{108}{4}

Therefore, the value of x is 27°.

Now,

2x° = (2×27)°= 54°

(2x+12)° = 2×27°+12°= 66°.

(x+2)= 27+ 2= 29°

Now, The left angle is 27°.

Therefore, The answer is option A.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
Mr. Moore planted a tree in his backyard. His tree grew 3 1/3 feet over five years. if his tree grew at the same rate each year,
alina1380 [7]

Answer:

D. 2/3 per year.

Step-by-step explanation:

3 1

3

÷ 5

=  

10

3

÷ 5

=  

10

3

×  

1

5

=  

10 × 1

3 × 5

=  

10

15

=  

10 ÷ 5

15 ÷ 5

=  

2

3

4 0
2 years ago
Solve<br> -7x = 21<br> X =<br> please help ASAP
Tomtit [17]

Answer: x = -3

Step-by-step explanation:

i simply divided by -7, in order to get x by itself.

-7/-7x = 21/-7

that cancels out the -7 on the left side, and leaves us with -3 on the right side!

x = -3

6 0
3 years ago
Read 2 more answers
P(x)=3x^2+12x+7 find coordinates of vertex and intercepts
kotegsom [21]
Te x intercepts are where the graph crosses the x axis or wher y=0
the y intercept is where the graph crosses the y axis or where x=0

to find vertex, here is a hack
the x coordinate of the vertex for an equation in form ax^b+bx+c=y is -b/2a

so
y=3x^2+12x+7
-b/2a=-12/2(3)=-12/6=-2
sub that back
y=3(-2)^2+12(-2)+7
y=3(3)-24+7
y=9-17
y=-8

vertex is (-2,-8)

intercepts
x intercept is where y=0

0=3x^2+12x+7
using quadratic formula
x=(-6-√15)/3 and (-6+√15)/3
xints at ((-6-√15)/3,0) and ((-6+√15)/3,0)

yint is where x=0
set x=0
y=7
yint is at y=7 or (0,7)


vertex at (-2,-8)
xints at x=\frac{-6+ \sqrt{15} }{3} and \frac{-6- \sqrt{15} }{3} or at the points ( \frac{-6+ \sqrt{15} }{3} , 0) and (\frac{-6- \sqrt{15} }{3},0)
yint at y=7 or at (7,0)
8 0
3 years ago
Which expression is equivalent to this quotient?
Musya8 [376]
It looks like there aren't many great matches for your search
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5 0
3 years ago
Read 2 more answers
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