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olasank [31]
3 years ago
11

What is the GCF of and 55 and 80 *

Mathematics
1 answer:
Zarrin [17]3 years ago
3 0

The Greatest Common Factor of 55 and 80 is 5.

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How do you figure out the answer?
svp [43]

we can divide the composite shape into on quadrilateral and triangle as shown in the diagram. since the line that joins the two shape is parallel to the base AB, the angle DEC is 85°.The angle CEA is 180°- angle DEC = 180-85=95. Angle BCE is sum of angle CEA, ABC and EAB subtracted from360°= 360°-(95+95+85)=85°. Angle DCE is 120°- ECB=35°. So, angle CDE = 180°-(35°+85°)= 60°. For reference see the diagram.

7 0
3 years ago
If a person was to buy 57 pounds of chocolate & it was 32$ a pound how much would it cost
Scilla [17]

Answer:

$1,824

Step-by-step explanation:

57*32 = 1,824.

4 0
2 years ago
The number of unread emails in Bryan’s account is 100. This number grows by 15 unread emails a day. The function N(t)=100+15t re
miv72 [106K]

Answer:

205

Step-by-step explanation:

Given

N(t) = 100 + 15t is the equation of the relation.

We're asked to find N(7)

Taking a look at the question again and putting it side by side the equation

N(t)

N(7)

We can deduce that t = 7, and as such, solve for it in the equation given

N(7) = 100 + 15(7)

N(7) = 100 + 105

N(7) = 205

Therefore, the number of unread mails after 7 days will be 205

8 0
2 years ago
Determine the number of subsets of {12, 13, 14}
Alex787 [66]

Answer:

8

Step-by-step explanation:

{ }

{12} {13} {14}

{12, 13} {12, 14} {13,14}

{12, 13, 14}

Total: 8

7 0
2 years ago
A bag contains 6 green counters, 4 blue counters and 2 red counters. Two counters are drawn from the bag at random without repla
Svetach [21]

Answer:

24.24%

Step-by-step explanation:

In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12

Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.

\frac{4}{12} * \frac{8}{11} =   \frac{32}{132} or 0.2424 or 24.24%

8 0
3 years ago
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