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mariarad [96]
3 years ago
14

The question is:

Mathematics
1 answer:
saul85 [17]3 years ago
8 0
f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1

(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\  \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a

Therefore, (fof^{-1})(a) = (f^{-1}of)(a) = a

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By rounding to 1 significant figure , estimate <br><br> 40.73 x 1.06<br><br> Anyone know?
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1) 40.73 to 1 significant figure = 40.

2) 1.06 to 1 significant figure = 1.

3) Therefore, we just multiply 40 by 1, which equals 40.

FURTHER EXPLANATION (IF NEEDED):

With significant figures, whole numbers such as 10, 20, 50 etc. have 1 significant figure. This is because the 0 does not count as a significant figure.

With decimals, all numbers after the decimal point are also included as significant figures (even 0). E.g. 40.73 has 4 significant figures and 1.06 has 3 significant figures.

EXAMPLES (IF NEEDED):

Rounding to 2 significant figures:

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  • 1.06 = 1.1

Rounding to 3 significant figures:

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Rounding to 4 significant figures:

  • 40.73 = 40.73 (already in 4 significant figures)
  • 1.06 = 1.060 (0 is counted as a significant figure if there is a decimal or another number comes after that 0)

E.g. 1006 has 4 sig figs, while 1060 would have 3 sig figs because the last 0 is not counted as a significant figure. 10.60 would have 4 sig figs because of the decimal.

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