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4 years ago

Consider the following model:

Mathematics

1 answer:

SSSSS [86.1K]4 years ago

8 0

Answer:

a. 3

Step-by-step explanation:

An independent variable is the variable that is changed in an experiment to test its effects on the dependent variable. i.e. inputs

A dependent variable is the variable being tested, measured or predicted in an experiment. I.e a outcome

In this case, the the effects of the amount tutors are paid a week before exam, the amount of sleep before exam and the number of study hours are input variables to determine or predict a students score in exam

The independent variables are;

x1 =represents the amount paid to a tutor (in dollars) in the week before the exam

x2 = represents the number of hours of sleep in the week before the exam

x3 = number of study hours in the week before the exam

The dependent variable is the exam score

B0, B1, B2,B3, B4 are coefficients

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Leona [35]

Answer with Step-by-step explanation:

We are given that u and v are functions of x and both are differentiable at x=0

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Using this formula

Then , we get

$[\frac{d(uv)}{dx}]_{x=0}=u'(0)v(0)+u(0)v'(0)=7(2)+4(1)=14+4=18$

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b. $\frac{d(u/v)}{dx}=\frac{u'v-uv'}{v^2}$

$[\frac{d(u/v)}{dx}]_{x=0}=\frac{u'(0)v(0)-u(0)v'(0)}{v^2(0)}=\frac{7(2)-4(1)}{2^2}=\frac{14-4}{4}=\frac{10}{4}=\frac{5}{2}$

$[\frac{d(u/v)}{dx}]_{x=0}=\frac{5}{2}$

$[\frac{d(v/u)}{dx}]_{x=0}=\frac{v'(0)u(0)-v(0)u'(0)}{u^2(0)}=\frac{1(4)-7(2)}{4^2}$

$[\frac{d(v/u)}{dx}]_{x=0}=\frac{-10}{16}=\frac{-5}{8}$

d. $\frac{d(-6v-9u)}{dx}=-6v'-9u'$

$[\frac{d(-6v-9u)}{dx}]_{x=0}=-6v'(0)-9u'(0)=-6(1)-9(7)=-6-63=-69$

$[\frac{d(-6v-9u)}{dx}]_{x=0}=-69$

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Step-by-step explanation:

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