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faltersainse [42]
3 years ago
9

choose the single logarithm expression that is equivalent to the one shown 1 / 3 log 3x + 2 / 3 log 3x​

Mathematics
1 answer:
alexgriva [62]3 years ago
6 0

Answer:

\log (3x)

Step-by-step explanation:

The given logarithmic expression is:

\frac{1}{3}\log(3x)+ \frac{2}{3}\log(3x)

This is the same as:

\frac{1}{3}\log(3x)+ \frac{1}{3}\log(3x)^2

\frac{1}{3}(\log(3x)+ \log(3x)^2)

We now apply the product rule to get:

\frac{1}{3}\log(3x)\times (3x)^2

\frac{1}{3}\log (3x)^3

We now apply the power rule to get;

\frac{3}{3}\log (3x)=\log (3x)

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Emerson deposited $194 into the bank. What will the balance be if Emerson left the money there for 7 years with an interest rate
SOVA2 [1]

Answer:

You just have to round to the cent place to get your answer

Step-by-step explanation:

Hope it helped!

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3 years ago
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The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?
Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(-6, 2)) = (x_1, y_1)

B(2, 6) = (x_2, y_2)

AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}

AB = \sqrt{(8)^2 + (4)^2}

AB = \sqrt{64 + 16} = \sqrt{80}

AB = 8.9 (nearest tenth)

Distance between B(2, 6) and C(7, 1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(2, 6) = (x_1, y_1)

C(7, 1) = (x_2, y_2)

BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}

BC = \sqrt{(5)^2 + (-5)^2}

BC = \sqrt{25 + 25} = \sqrt{50}

BC = 7.1 (nearest tenth)

Distance between C(7, 1) and D(3, -5):

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(7, 1) = (x_1, y_1)

D(3, -5) = (x_2, y_2)

CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}

CD = \sqrt{(-4)^2 + (-6)^2}

CD = \sqrt{16 + 36} = \sqrt{52}

CD = 7.2 (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

D(3, -5) = (x_1, y_1)

A(-6, 2) = (x_2, y_2)

DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}

DA = \sqrt{(-9)^2 + (7)^2}

DA = \sqrt{81 + 49} = \sqrt{130}

DA = 11.4 (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0
3 years ago
These types of building blocks are an energy source.
pychu [463]
The answer is A. Fats 

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3 years ago
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Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every
Nutka1998 [239]

Answer:

25 seconds

Step-by-step explanation:

Hi there!

In order to answer this question, first we need to know how many bolts per second are produced by each machine, this can be known by dividing the number of bolts by the time it takes.

For machine A:

A = \frac{120 bolts}{40 s}= 3 \frac{bolts}{s}

For machine B:

B = \frac{100 bolts}{20 s}= 5 \frac{bolts}{s}

So, if the two machines run simultaneously, we will have a rate of prodcution of bolts equal to the sum of both:

A+B=(3+5)\frac{bolts}{s}=8\frac{bolts}{s}

Now, we need to know how much time it will take to producee 200 bolts, to find this out we need to divide the amount of bolts by the production rate:

t = \frac{bolts}{ProductionRate}= \frac{200 bolts}{8 \frac{bolts}{s} }

The <em>bolts</em> unit cancell each other and we are left with <em>seconds</em>

t = \frac{200}{8} s = 25 s

So it will take 25 seconds to produce 200 bolts with machine A and B running simultaneously.

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If f(x) = 5x, what is f^-1(x)?<br> F(x) = -5x<br> of(x)-<br> F(x) = 5*<br> O F(x) = 5x
Oksana_A [137]

Answer:

f^-1 (x) = x/5

Step-by-step explanation:

f(x) = 5x

Replace f(x) with y

y= 5x

Exchange x and y

x = 5y

Solve for y

Divide each side by 5

x/5 = 5y/5

x/5 = y

The inverse is x/5

3 0
3 years ago
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