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Pavel [41]
3 years ago
12

The troposphere extends from the Earth's surface to a height of 6–12 miles, depending on the location and the season. If a plane

is flying at an altitude of 5.8 miles, and the troposphere is 8.6 miles deep in that area, how much higher can the plane go without leaving the troposphere?
Mathematics
1 answer:
Anni [7]3 years ago
8 0

Answer:

2.8 miles higher the plane go without leaving the troposphere?

Step-by-step explanation:

Troposphere height on different locations= 6-12 miles  

plane altitude at present flight = 5.8 miles.  

Troposphere deepness from the present flight= 8.6 miles  

So  from present altitude till troposphere=   8.6-5.8= 2.8 miles  

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Answer & Explanation:

Volume can be expressed in cubic centimeters, or in milliliters. One milliliter is equal to one cubic centimeter, or one cc, for short. If your initial measurements are given in inches, multiply them by 2.54 to convert them to centimeters.

7 0
2 years ago
A 2-column table with 5 rows. The first column is labeled x with entries negative 4, negative 1, 0, 2, 3. The second column is l
Elenna [48]

Answer:

f(x)= 1.8x + 1

Step-by-step explanation:

Just got it right on edge :)

7 0
2 years ago
Một lô hàng chứa rất nhiều sản phẩm, trong đó tỷ lệ sản phẩm loại tốt là 70%. chọn ngẫu nhiên từ lô hàng ra 5 sản phẩm. gọi X là
den301095 [7]

trả lời : lâp bảng

X=0 thì xác suất lấy ra được sản phẩm tốt là 5*30%=1,5%

X =1 thì xác suất lấy ra được là 1* 70%*4*30%=0,84%

X=2 thì xác suất lấy ra được sản phẩm tốt là 2*70%*3*30%=1,26%

X=3 thì xác suất lấy ra được sản phẩm tốt là 3*70%*2*30%=1,26%

X=4 thì xác suất lấy ra được sản phẩm tốt là 4*70%*1*30%=0,84%

X=5 thì xác suất lấy ra được sản phẩm tốt là 5*70%=3,5%

X 0 1 2 3 4 5

P 1,5 0,84 1,26 1,26 0,84 3,5

b,

E(x)= 1,5*0+ 0,84*1+1,26*2+1,26*3+0,84*4+3,5*5=28

E(x^2)=1,5*0^2+0,84*1^2+1,26*2^2+1,26*3^2+0,84*4^2+3,5*5^2=118,16

===> V(x)= (E(x))^2-E(x^2)=28^2-118,16=665,84

8 0
3 years ago
Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0
Arada [10]

Answer:

b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0

Step-by-step explanation:

The given matrix addition is

B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

We need to find the elements of matrix B.

Let B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}

Substitute the value of matrix.

\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

After addition of two matrix we get

\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

On equating both sides.

b_{11}+15=1\Rightarrow b_{11}=-14

b_{12}-7=2\Rightarrow b_{12}=9

b_{13}+4=12\Rightarrow b_{13}=8

b_{21}+0=4\Rightarrow b_{21}=4

b_{22}+1=0\Rightarrow b_{22}=-1

b_{23}+2=2\Rightarrow b_{23}=0

Therefore, the elements of matrix B are b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0.

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