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vladimir2022 [97]
3 years ago
5

16x²-81=0 solve the following quadratic equation

Mathematics
2 answers:
arsen [322]3 years ago
7 0
16x^2-81=0\\\\(4x)^2-9^2=0\\\\(4x-9)(4x+9)=0\iff4x-9=0\ \vee\ 4x+9=0\\\\4x=9\ \vee\ 4x=-9\\\\x=\frac{9}{4}\ \vee\ x=-\frac{9}{4}


or\\\\16x^2-81=0\\\\16x^2=81\ \ \ \ /:16\\\\x^2=\frac{81}{16}\\\\x=\pm\sqrt\frac{81}{16}\\\\x=-\frac{\sqrt{81}}{\sqrt{16}}\ \vee\ x=\frac{\sqrt{81}}{\sqrt{16}}\\\\x=-\frac{9}{4}\ \vee\ x=\frac{9}{4}
In-s [12.5K]3 years ago
4 0
16x^2-81=0
(4x-9)(4x+9)
x=9/4 or x=-9/4
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Step-by-step explanation:

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See in the explanation

<h2>Explanation:</h2>

In this exercise, <em>we have the following points:</em>

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<h3>For (2):</h3>

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<h3>For (3):</h3>

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<h2>Learn more:</h2>

About lines: brainly.com/question/12169569

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