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zaharov [31]
3 years ago
9

Which is greater 34/18 or 1 5/6

Mathematics
1 answer:
Zinaida [17]3 years ago
3 0
34/18 is 1 8/9. 34/18 is greater than 1 5/6.
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Help me pleaaseee!!!!!
jarptica [38.1K]

Answer: 5^7

Step-by-step explanation: When multiplying exponents with the same base number you add the exponents together. For example 2^4 x 2^3 will multiply to a product of 2^7.

8 0
4 years ago
Read 2 more answers
a boat is going 144 miles upstream on a river. the speed of the boat in still water is 60 miles per hour. the speed of the river
Katena32 [7]

Answer:

Let  b  =  rate of the boat.

Let  r  =  rate of the river.

The rate going downstream is  b + r.

The rate going upstream is  b - r.

rate x time  =  distance

4(b + r)  =  144     --->     b + r  =  36     [divide both sides by 4]

9(b - r)  =  144      --->     b - r  =  16      [divide both sides by 9]

Add town:                          2b  =  52  

Divide by :                           b  =  26  mi/hr

                                           r  =  10  mi/hr

Step-by-step explanation:

5 0
3 years ago
Bill's golf bag contains 9 white golf balls, 6 yellow golf balls, 1 orange golf ball, and 1 pink golf ball. Without looking, Tim
BaLLatris [955]

Answer:

The correct answer is 0.0330 and the events are independent.

Step-by-step explanation:

Total number of balls in Bill's golf bag = 17

Let A be the event of drawing a white ball and B be the event of drawing an orange ball.

Number of white balls Bill has in his bag is 9.

Probability of the event A in the first draw = \frac{9}{17}

Number of orange ball in Bill's bag is 1.

Probability of event B in the second draw = \frac{1}{16}

Thus total probability for Tim to tee off with a white ball and putt with an orange ball = \frac{9}{272} = 0.0330

The above events are independent on each other.

4 0
4 years ago
A certain company makes three grades (A, B, and C) of a particular electrical component. Historically, grade A components have a
IrinaK [193]

Answer:

following are the solution to this question:

Step-by-step explanation:

In part (a):

Phase 1: Identifies a reasonable confidence period with both the title or form and checks suitable conditions. one z-interval test, p, that true percentage of defective parts in such a lot of Clauses:

1. Unique component sampling

2. This survey size is enough, to the fact to conclude the composition of that percentage of a sample was roughly natural, which the amount for successes and the number of losses are either greater than 10 (or 5 or 15). Needs to check: A 200-component representative selection of a big batch was picked. Each has far more than 15 achievements or failures (16 and 184).

Phase 2: Mechanisms Correct Pick problems for Pink and Blue it Committee of a College. Similar products are part of the program of a College Board. It is prohibited for such resources to be used and distributed online or in a printed form far beyond the participation of the college in the package, which leads to intervals (0.0424, 0.1176).

Phase 3: Background analysis In just this study, we consider 95% of its computed value to have between 4.24% and 11.76% for both the real number of defective components within the batch.

In part (b):

Its standard deviation of 95 percent found in Part (a) allows a company to eliminate class A as its 2 percent faulty rate is not among the computed value within this interval. It period however does not enable the company to decide between levels B and C, since the two faulty rates (5% and 10%) were examined.

Scoring: In 4 components the question is rated. Section 1 comprises part (a) step 1; part (a) or step 2 comprises of the part (a), part (3), part (a), and part (4) (b). The part was marked as correct (E), partly right (P) (I).

4 0
3 years ago
The sum of the ages of Mr Lin and his son Ethan is 38 years. In three years' time, Mr Lin will be three times as old as his son.
Sati [7]

Answer:

Mr.Lin's present age is 30 years now. His son is 8 years old now.

Step-by-step explanation:

Let L = Mr.Lin's present age,

   S = his son's present age.

First equation  is

L + S = 38.       (1)

The second equation is  

L + 3 = 3*(S+3)   (2)   ("In three years' time, Mr.Lin will be three times as old as his son.")

From (1), express S = 38-L and substitute it into (2). You  will get

L + 3 = 3*((38-L)+3),   or

L + 3 = 114 - 3L + 9,

4L = 114 + 9 - 3,  

4L = 120,

L = 30.

8 0
3 years ago
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