Answer:
Y=-5/3x-1
y=2/3x-8
If you are adding then it is:
7x=21
x=3
Step-by-step explanation:
5x+3y=-3
3y=-5x-3
y=-5/3-1
2x-3y=24
-3y=-2x+24
y=2/3x-8
Answer:
Equation of the circle (x-3)²+(y-5)²=(6.4)²
x² -6x +9 +y² -10y +25 = 40.96
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given endpoints of diameter P(−2, 1) and Q(8, 9)
Centre of circle = midpoint of diameter
Centre = 
Centre (h, k) = (3 , 5)
<u><em>Step(ii):-</em></u>
The distance of two end points
PQ = 

PQ = √164 = 12.8
Diameter d = 2r
radius r = d/2
Radius r = 6.4
<u><em>Final answer:-</em></u>
Equation of the circle
(x-h)²+(y-k)² = r²
(x-3)²+(y-5)²=(6.4)²
x² -6x +9 +y² -10y +25 = 40.96
x² -6x +y² -10y = 40.96-34
x² -6x +y² -10y -7= 0
Step-by-step explanation:
since in a triangle each side must be shorter than the sum of the other 2 sides (otherwise the end points cannot connect, and there is no triangle), the necessary inequality condition must be
side < 1 + 2 = 3
so,
side < 3
for a lower limit let's go through the cases
1 < 2 + side (is always true)
2 < 1 + side
1 < side (side must be larger than 1)
and again
side < 1 + 2 = 3
side < 3
so the full restriction for the third side is
1 < side < 3
Answer:
Where is it I don't see it?
Step-by-step explanation: