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Paraphin [41]
2 years ago
8

How many 1/2 cup servings are in a box of oatmeal that contains 6 3/4

Mathematics
1 answer:
anzhelika [568]2 years ago
7 0

6 and 3/4 divided by 1/2

27/4 divided by 1/2

27/4 * 2/1 = 27/2 = 13 and 1/2

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6th grade math help me, please :))
Gelneren [198K]

Answer:

\sf a) \ 2.5\\b) \ 7.5

Step-by-step explanation:

\displaystyle \frac{250}{100}

\sf Express \ as \ a \ decimal.

=2.5

\sf Multiply \ 3\% \ with \ 250.

\displaystyle 250 \times \frac{3}{100}

\displaystyle \frac{750}{100}=7.5

5 0
3 years ago
On a coordinate plane, 3 triangles are shown. Triangle B C D has points (1, 4), (1, 2), (5, 3). Triangle B prime C prime D prime
Tresset [83]

The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y ⇒ last answer

Step-by-step explanation:

Let us revise the reflection across the y-axis , horizontal translation

and vertical translation

1. If point (x , y) is reflected across the y-axis, then its image is (-x , y)

2. If point (x , y) is translated h units to the right, then its image is

   (x + h , y), if translated h units to the left, then its image is (x - h , y)

3. If point (x , y) is translated k units up, then its image is (x , y + k),

   if translated k units down, then its image is (x , y - k)

∵ The vertices of triangle BCD are (1 , 4) , (1 , 2) , (5 , 3)

∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)

∵ The x-coordinates of the vertices of Δ B'C'D' have the same

   magnitude of x-coordinates of Δ BCD and opposite signs

∴ Δ B'C'D' is the image of Δ ABC after reflection across the y-axis

∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)

∵ The vertices of triangle B''C''D'' are (5 , -1) , (5 , -3) , (1 , -2)

∵ The image of -1 is 5 and the image of -5 is 1

∴ The x-coordinates of the vertices of triangle B'C'D' are added by 6

∵ The image of 4 is -1 , image of 2 is -3 and the image of 3 is -2

∴ The y-coordinates of the vertices of triangle B'C'D' are subtracted

   by 5

∴ Δ B"C"D" is the image of Δ B'C'D' by translate 6 units to the right

  and 5 units down ⇒ (x + 6 , y - 5)

The rule which describe the composition of transformations that

maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis composition translation of 6 units x,

negative 5 units y

Learn more:

You can learn more about reflection in brainly.com/question/11203617

#LearnwithBrainly

3 0
3 years ago
Read 2 more answers
I need help on this question anyone know this ?
WITCHER [35]

Answer:

y = 4(2)^{x}

Step-by-step explanation:

An exponential function in standard form is

y = a b^{x}

Use ordered pairs from the table to find a and b

Using (0, 4), then

4 = a b^{0} ( note that b^{0} = 1 ), so

a = 4, then

y = 4 b^{x}

Using (1, 8)

8 = 4 b^{1} = 4b ( divide both sides by 4 )

b = 2

y = 4 (2)^{x} ← represents the values in the table

7 0
3 years ago
A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
Find a rational number halfway in between two numbers<br><br> 4/7 and 1/8
user100 [1]
I think it’s 5/14 not positive but pretty sure

8 0
3 years ago
Read 2 more answers
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