Question

Given ∆qrs ~ ∆Xyz, what is the value of tan(q)

Answer 1

We know that

in the triangle QRS
tan Q=RS/SQ

in the triangle XYZ
tan X=YZ/ZX---------> tan X=9/12------> tan X=3/4

so
∆qrs ~ ∆Xyz
tan Q=tan X----------> tan Q=3/4

the answer is
tan Q=3/4

Answer 2

The correct answer is

B. $\frac{3}{4}$

Given △QRS ~ △XYZ, the value of tan(Q) is $\frac{3}{4}$.

$|Huntrw6|$