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faltersainse [42]
3 years ago
14

Given ∆qrs ~ ∆Xyz, what is the value of tan(q)

Mathematics
2 answers:
alexandr402 [8]3 years ago
6 0
We know that

in the triangle QRS
tan Q=RS/SQ

in the triangle XYZ
tan X=YZ/ZX---------> tan X=9/12------> tan X=3/4

so
<span>∆qrs ~ ∆Xyz
</span>tan Q=tan X----------> tan Q=3/4

the answer is
tan Q=3/4
never [62]3 years ago
4 0

The correct answer is

B. \frac{3}{4}

Given △QRS ~ △XYZ, the value of tan(Q) is \frac{3}{4}.

|Huntrw6|

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