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Scrat [10]
2 years ago
10

Which equation is equal to 4^ x+3=64

Mathematics
1 answer:
Tems11 [23]2 years ago
4 0

Answer:

x=ln(61)/ln(4)

Step-by-step explanation:

4^x+3=64

4^x=64-3

4^x=61

x=ln(61)/ln(4)

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Given g(x) = 2x + 5, find g(1)
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Answer:

g(1) =7

Step-by-step explanation:

g(x) = 2x + 5

Let x=1

g(1) = 2(1) +5

      = 2+5

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3 years ago
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A class of 30 is divided into 2 groups such that the size of the smaller group is 2/3 the size of the larger group. How large is
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I kinda did a lil of this in my head so i might not be 100% correct, but i would say the bigger group is 20 and the smaller group is 10

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The circumference can be obtained fairly easily by simply substituting the d in c = πd for the colony's given diameter of 12 mm. Performing that calculation using the approximation of π ≈ 3.14, we obtain a circumference of 12 x 3.14 = 37.68 mm.

To find the radius, remember how the diameter and radius of a circle are defined. The radius is a length extending from the center of a circle to a point on its circumference, and a diameter is a line extending from one point on the circle's circumference to an opposite point, passing through the circle's center along the way. The diameter can, in this way, be defined as twice the length of the radius, which means we can find the radius of a circle by taking half of its diameter. In this case, our diameter is 12 mm, so our radius would be 6 mm.
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Choose the correct conic section to match the equation. 16x 2 - y 2 = 16 parabola hyperbola ellipse circle
Nastasia [14]

The equation 16x² - y² = 16 represents a hyperbola ⇒ 2nd answer

Step-by-step explanation:

The general form of the equation of a conic is

Ax² + Bxy + Cy² + Dx + Ey + F = 0, where A, B, C, D, E, and F

are constants

To find the type of conic that the equation represent find B² - 4AC

1. B² - 4AC < 0 and the conic is exist, then it's ellipse or circle,

   if A = C, (non-zero) then it is a circle, if A ≠ C, then it is an ellipse

2. B² - 4AC = 0 and the conic is exist, then it's a parabola

3. B² - 4AC > 0 and the conic is exist, then it's a hyperbola

∵ The equation is 16x² - y² = 16

- Subtract 16 from both sides

∴ 16x² - y² - 16 = 0

∵ Ax² + Bxy + Cy² + Dx + Ey + F = 0

∴ A = 16 , B = 0 , C = -1 , D = 0 , E = 0 , F = -16

∵ B² - 4AC = (0)² - 4(16)(-1)

∴ B² - 4AC = 64

∵ 64 > 0

∵ B² - 4AC > 0

∴ The conic is hyperbola

The equation 16x² - y² = 16 represents a hyperbola

Learn more:

You can learn more about hyperbola in brainly.com/question/4054269

#LearnwithBrainly

7 0
3 years ago
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