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morpeh [17]
3 years ago
6

Point (-4, 3) lies in Quadranta. 1 b.2 c.3 d.4​

Mathematics
1 answer:
sdas [7]3 years ago
5 0
It lies quadrant
in C.3
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A box is filled with 2 brown cards,8 yellow cards, and 8 green cards. A card is chosen at random from the box. What is the proba
IgorLugansk [536]

2 brown, 8 yellow, 8 green, thus our sample space is 2+8+8 = 18.

What is the probability that the card is NOT yellow?  How many non-yellow are there?  well 2 + 8 = 10, favorable outcomes.

\bf \cfrac{\stackrel{\textit{favorable outcomes}}{10}}{\underset{\textit{sample space}}{18}}\implies \cfrac{5}{9}\implies 0.\overline{555}\qquad \approx \qquad 55.6\%

8 0
3 years ago
In ΔKLM, the measure of ∠M=90°, the measure of ∠K=78°, and KL = 35 feet. Find the length of MK to the nearest tenth of a foot.
Margaret [11]

Answer:

7.3 feet

Step-by-step explanation:

osK=

hypotenuse

adjacent

​

=

35

x

​

\cos 78=\frac{x}{35}

cos78=

35

x

​

35\cos 78=x

35cos78=x

Cross multiply.

x=7.2769\approx \mathbf{7.3}\text{ feet}

x=7.2769≈7.3 feet

Type into calculator and round to the nearest tenth of a foot.

4 0
3 years ago
Read 2 more answers
The diagram shows a right-angled triangle.
Karo-lina-s [1.5K]

Answer:

sorry j don't have my calculator but

sine of angle x°=opposite 6cm/9cm

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8 0
2 years ago
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there are 104 red candies in a candy machine. this represents 26% of the candy in the machine. how many total are in the candy m
Alborosie

There are 400 candies in the machine.

Step-by-step explanation:

Given,

Number of red candies in machine = 104

This represents 26% of the total candies.

Let,

x be the total candies in the machine.

According to statement;

26% of x = 104

\frac{26}{100}*x=104\\0.26x=104

Dividing both sides by 0.26

\frac{0.26x}{0.26}=\frac{104}{0.26}\\x=400

There are 400 candies in the machine.

Keywords: percentage, division

Learn more about percentages at:

  • brainly.com/question/317697
  • brainly.com/question/317616

#LearnwithBrainly

6 0
3 years ago
Solve the formula t=v+k/g for g
Brut [27]
t=v+\frac{k}{g}\\\\v+\frac{k}{g}=t\ \ \ \ |subtract\ v\ from\ both\ sides\\\\\frac{k}{g}=t-v\iff\frac{g}{k}=\frac{1}{t-v}\ \  \ \ |multiply\ both\ sides\ by\ k\neq0\\\\\boxed{g=\frac{k}{t-v}}
8 0
3 years ago
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