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galben [10]
3 years ago
5

( 20 points + brainliest for the correct answer!!!) ASA AAS CONGRUENCE

Mathematics
1 answer:
Olegator [25]3 years ago
5 0
A. AAS
B. SAS
C. ASA

Just look at what order they come in. Lmk if you need further help.
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Circumference and Area questions look at the picture
Helga [31]

Note that the formula for the circumference of a circle is πd, while the formula for the area of a circle is πr².

π≈3.14

A. C=πd

Simply plug in the numbers into the formula.

Diameter=Radius*2

17*2=34

C=34(π)

B. (π)(5²)

Plug in the numbers into the formula. Remember that half of the diameter is the radius.

C.  (π)(4.5)

There are two possible formulas that could be used to calculate the circumference of a circle: πd and 2πr.

The expression above is simply multiplying the circle's radius times pi. Therefore, it is not a method that could be used to find the circumference of a circle.

D. (π)(6.5²)

Remember that the formula for calculating the area of a circle is πr².

Half of the diameter is 6.5 (13.5/2=6.5). 6.5 cm. is the radius. Now just plug the numbers into the formula.

(π)(6.5²)

Therefore, the last answer choice is the correct answer.

5 0
3 years ago
Write in simplest form:<br> 4 1/3 : 7
bagirrra123 [75]
The simplest form can be 13/3: 7 or 4.3:7
4 0
3 years ago
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Which point is not part of circle c?
Leona [35]
The conflict reaches a turning point. ... The crisis occurs before or at the same time as the climax. Climax. The climax is the result of the crisis. It is the high point<span> of the </span>story<span> for the reader.</span>
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3 years ago
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Please help!
qwelly [4]
It could be -1, 1, and 2
5 0
3 years ago
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If f x equals x -3 + g x equals 1 - x 2 - 9 find ( f og) (x and give any restrictions on its domain
evablogger [386]
\begin{gathered} f(x)=x-3 \\ g(x)=\frac{1}{x^2-9} \\ (\text{fog)(x)}=\frac{1}{x^2-9}-3 \end{gathered}

the denominator cannot be zero, because the division by zero is not defined, therefore:

\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}

Therefore the domain of (f o g)(x) is:

D\colon(-\infty,-3)\cup(-3,3)\cup(3,\infty)

3 0
1 year ago
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