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bonufazy [111]
3 years ago
9

Solve for x -13=x/2-3

Mathematics
1 answer:
kodGreya [7K]3 years ago
6 0

Answer: x = 20

Step-by-step explanation:

1) Move all terms to the left:

x-13-(x/2-3)=0

2) Get rid of parentheses

x-x/2+3-13=0

3) Multiply all the terms by the denominator

x*2-x+3*2-13*2=0

4) Add all the numbers together, and all the variables

-1x+x*2-20=0

5) Multiply elements

-1x+2x-20=0

6) Add all the numbers together, and all the variables

x-20=0

7) Move all terms containing x to the left, all other terms to the right

x=20

Hope This Helps (From My Notes)

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Answer:

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Step-by-step explanation:

5 0
3 years ago
Shawna buys 2 1/2 gallons of paint. If she uses 1/3 of it on the first day, how much does she have left?
Stolb23 [73]

Answer:

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Step-by-step explanation:

Hope this helps! Have a nice day!

4 0
3 years ago
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Step-by-step explanation:

y=15x represents a proportional relationship because y/x=15

y= -x represents a proportional relationship because y/x= -1.

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4 0
4 years ago
Lim x→π/2 1-sinx/cot^2x<br>any genious help please ​
Simora [160]

Rewrite the limand as

(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = (1 - sin(<em>x</em>)) / (cos²(<em>x</em>) / sin²(<em>x</em>))

… = ((1 - sin(<em>x</em>)) sin²(<em>x</em>)) / cos²(<em>x</em>)

Recall the Pythagorean identity,

sin²(<em>x</em>) + cos²(<em>x</em>) = 1

Then

(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = ((1 - sin(<em>x</em>)) sin²(<em>x</em>)) / (1 - sin²(<em>x</em>))

Factorize the denominator; it's a difference of squares, so

1 - sin²(<em>x</em>) = (1 - sin(<em>x</em>)) (1 + sin(<em>x</em>))

Cancel the common factor of 1 - sin(<em>x</em>) in the numerator and denominator:

(1 - sin(<em>x</em>)) / cot²(<em>x</em>) = sin²(<em>x</em>) / (1 + sin(<em>x</em>))

Now the limand is continuous at <em>x</em> = <em>π</em>/2, so

\displaystyle\lim_{x\to\frac\pi2}\frac{1-\sin(x)}{\cot^2(x)}=\lim_{x\to\frac\pi2}\frac{\sin^2(x)}{1+\sin(x)}=\frac{\sin^2\left(\frac\pi2\right)}{1+\sin\left(\frac\pi2\right)}=\boxed{\frac12}

4 0
3 years ago
A school is building a rectangular stage for its chorus. The stage must have a width of 4 feet. The area of the stage must be at
slavikrds [6]

Answer: Length ≥ 6 feet

Step-by-step explanation:

The area of a rectangle= length × width

In this case, the width is 4 feet and the area of the stage must be at most 24 square feet.

The inequality that describes the possible lengths (in feet) of the stage would be:

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Therefore, the length must be at most 6 feet.

4 0
3 years ago
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