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Lilit [14]
3 years ago
7

Which equation represents a proportional relationship?

Mathematics
1 answer:
Mice21 [21]3 years ago
4 0

Good evening ,

______

Answer:

y=15x and y= -x

___________________

Step-by-step explanation:

y=15x represents a proportional relationship because y/x=15

y= -x represents a proportional relationship because y/x= -1.

:)

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Factor completely 3a4y3 − 12a3y2 + 6a2y.
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Step-by-step explanation:

3a^4y^3-12a^3y^2+6a^2y=(3a^2y)(a^2y^2)-(3a^2y)(4ay)+(3a^2y)(2)\\\\=(3a^2y)(a^2y^2-4ay+2)

5 0
2 years ago
In an architecture class the students built a scale model of an office building. If the scale is 1 in. = 12 feet and the model i
iogann1982 [59]

Answer:

102 feet tall

Step-by-step explanation:

12 multiplied by 8 1/2 to get 102

7 0
3 years ago
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The probability of drawing a pearl bead out of a bag of mixed beads is 2/3. What is the probability of drawing a bead which is n
Georgia [21]

Answer:

\frac{1}{3} probability of drawing a bead which is not a pearl

Step-by-step explanation:

For each bead that you draw, there are only two possible outcomes. Either it is a pearl bead, or it is not. The sum of these probabilities = 100% = 1.

So

2/3 probability of drawing a pearl bead.

p probability of drawing a non pearl bead.

What is the probability of drawing a bead which is not a pearl?

p + \frac{2}{3} = 1

p = 1 - \frac{2}{3}

p = \frac{3*1 - 2}{3}

p = \frac{1}{3}

\frac{1}{3} probability of drawing a bead which is not a pearl

7 0
3 years ago
A<br> Positive<br> b<br> Undefined<br> c<br> Negative<br> d<br> Zero
VLD [36.1K]
I believe that the answer would be
A. Positive
4 0
3 years ago
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If f(x) is differentiable for the closed interval [-1, 4] such that f(-1) = -3 and f(4) = 12, then there exists a value c, -1&lt
Alex_Xolod [135]

Answer: Choice A,   f ' (c) = 3

============================================

Work Shown:

f(-1) = -3 means the point (-1,-3) is on the f(x) curve.

f(4) = 12 means (4,12) is on the f(x) curve as well.

Compute the slope of the line through those two points.

Slope formula

m = (y2 - y1)/(x2 - x1)

m = (12 - (-3))/(4 - (-1))

m = (12+3)/(4+1)

m = 15/5

m = 3

The slope of the secant line through (-1,-3) and (4,12) is m = 3

Through the mean value theorem (MVT), there exists at least one value c such that f ' (c) = 3, where -1 < c < 4, and f(x) is a continuous and differentiable function on this interval in question.

Visually, there exists at least one tangent line that has the same slope of the secant line mentioned. Lines with equal slopes, and different y intercepts, are parallel.

5 0
3 years ago
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