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3 years ago

20POINTS! HELP ME PLZZ I NEED HELP WITH THIS IT IS DUE TOMORROW !!

Mathematics

1 answer:

ANTONII [103]3 years ago

8 0

Step-by-step explanation:

The denominators are 2, 3, and 4. The least common denominator is the least common multiple (LCM) of these numbers.

To find the LCM, first write the prime factorizations.

2 = 2¹

3 = 3¹

4 = 2²

The LCM is therefore 2² × 3 = 12.

Rewrite the fractions with a denominator of 12.

⁷/₄ + ¹/₂ + ⁵/₃ + ¹/₃ + ¹/₄ + ¹/₂

= ²¹/₁₂ + ⁶/₁₂ + ²⁰/₁₂ + ⁴/₁₂ + ³/₁₂ + ⁶/₁₂

Now that the denominators are the same, we can simply add the numerators.

= ⁽²¹⁺⁶⁺²⁰⁺⁴⁺³⁺⁶⁾/₁₂

= ⁶⁰/₁₂

= 5

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2 years ago

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Step-by-step explanation:

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2 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

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2 years ago

What does p equal in the equation 84,000p + 36,000m = 1,962, 800

Alex_Xolod [135]

Answer:

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Step-by-step explanation:

Step 1: Add -36000m to both sides.

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3 years ago