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3 years ago

11

20POINTS! HELP ME PLZZ I NEED HELP WITH THIS IT IS DUE TOMORROW !!

1 answer:

ANTONII [103]3 years ago

8 0

Step-by-step explanation:

The denominators are 2, 3, and 4. The least common denominator is the least common multiple (LCM) of these numbers.

To find the LCM, first write the prime factorizations.

2 = 2¹

3 = 3¹

4 = 2²

The LCM is therefore 2² × 3 = 12.

Rewrite the fractions with a denominator of 12.

⁷/₄ + ¹/₂ + ⁵/₃ + ¹/₃ + ¹/₄ + ¹/₂

= ²¹/₁₂ + ⁶/₁₂ + ²⁰/₁₂ + ⁴/₁₂ + ³/₁₂ + ⁶/₁₂

Now that the denominators are the same, we can simply add the numerators.

= ⁽²¹⁺⁶⁺²⁰⁺⁴⁺³⁺⁶⁾/₁₂

= ⁶⁰/₁₂

= 5

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Dillard's department store is having a huge sale where everything is 30% off. When you got to the cash register because you were

vlabodo [156]

Answer:

15.75

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3 years ago

Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)

Lisa [10]

Answer:

$f(x) = 4x^2 - 3x + 6$

Step-by-step explanation:

Quadratic function is given as $f(x) = ax^2 + bx + c$

Let's find a, b and c:

Substituting (0, 6):

$6 = a(0)^2 + b(0) + c$

$6 = 0 + 0 + c$

$c = 6$

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

$f(x) = ax^2 + bx + c$

$16 = a(2)^2 + b(2) + 6$

$16 = 4a + 2b + 6$

$16 - 6 = 4a + 2b + 6 - 6$

$10 = 4a + 2b$

$10 = 2(2a + b)$

$\frac{10}{2} = \frac{2(2a + b)}{2}$

$5 = 2a + b$

$2a + b = 5$ => (Equation 1)

Substituting (3, 33), and c = 6

$f(x) = ax^2 + bx + x$

$33 = a(3)^2 + b(3) + 6$

$33 = 9a + 3b + 6$

$33 - 6 = 9a + 3b + 6 - 6$

$27 = 9a + 3b$

$27 = 3(3a + b)$

$\frac{27}{3} = \frac{3(3a + b)}{3}$

$9 = 3a + b$

$3a + b = 9$ => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

$3a + b = 9$

$2a + b = 5$

$a = 4$

Replace a with 4 in equation 2.

$2a + b = 5$

$2(4) + b = 5$

$8 + b = 5$

$8 + b - 8 = 5 - 8$

$b = -3$

The quadratic function that represents the given 3 points would be as follows:

$f(x) = ax^2 + bx + c$

$f(x) = (4)x^2 + (-3)x + 6$

$f(x) = 4x^2 - 3x + 6$

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3 years ago

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Dovator [93]

Answer:

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