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Delvig [45]
3 years ago
12

The same, unknown bacteria is isolated from 20 sick individuals. Their samples were grown in culture and then placed in 10 healt

hy mice. Those mice started to show signs of a heightened immune response. To determine if the bacteria is pathogenic, what is the next step by using Koch’s postulates?
Biology
2 answers:
AleksAgata [21]3 years ago
4 0
<h2>Koch's Postulates.</h2>

Explanation:

The next step should be isolate the microorganism from the mice and check if it is identical to the original microbe.

According to Koch's postulates, a microbe can be considered as a causative agent of a disease only after all the following are established:

  • The microorganism should be present in all the organism suffering from the disease.
  • The isolated microorganism should be grown in pure culture.
  • The organism grown in the culture should be reintroduced in the susceptible but healthy host.
  • Finally the microorganism must be re-isolated from the experimental host an cultured to see whether it is identical to the original specific microorganism.

tino4ka555 [31]3 years ago
3 0

Answer:

The answer is "C"

Explanation:

"Reisolate it, and determine if it is the original unknown bacteria."

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Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (a
PilotLPTM [1.2K]

Answer:

The ear length will be 11 cm.

Explanation:

To know about the ear length of F1 generation, we need to know that how much length in centimeters is contributed by each of the alleles. As we know, each allele has the same value for contributing to the effect of ear length, hence we can divide the ear length by 4 to get our results.

As 6 divided by 4 is 1.5 hence, the allele a and b contribute to 1.5 cm of the length of the ear.

6 divided by 4 is 4, hence the alleles And B contribute to 4 cm of the length of the ear.

The F1 generation will have AaBb genotype hence, the lenght will be 4+1.5+4+1.5 = 11 cm.

6 0
3 years ago
Identify a probable reason that the dark moths survived while the light moths did not.
kirill [66]

Answer:

This question has little context, but I understand what you are trying to say.

The reason why dark moths survived while light moths weren't able to survive is due to the dark moths having conditions that allowed them to camouflage better than the light moths. An environmental condition that would allow this would be the dark moths and the light moths living in the same dark environment.

Explanation:

7 0
3 years ago
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Which of the following is a producer in the food web shown above?
Masja [62]
The answer is B HOPE THAT HELPS

3 0
3 years ago
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Alina [70]
A way scientist answer questions and solve problems
8 0
3 years ago
In squash, yellow seeds are dominant over green seeds. If two heterozygous yellow seed squash were crossed, what are the genotyp
Umnica [9.8K]

Answer:

The result of cross two squashes with yellow seeds is an offspring of squash with green seeds -dominant caracter- heterozygous and yellow seeds squashes in a genotype proportion 1:2:1  and phenotype proportion 3:1

Explanation:

The cross of two heterozygous individuals for a characteristic results in an offspring that will have both characteristics in pure and heterozygous form. It is a cross monohybrid which complies with the principle of independent segregation exposed by Mendel.

For the characteristic "seed color" the green color would be G and yellow represented as g.

At the cross of two heterozygous squashs:

- Parents: Gg X Gg

- <u>Punnett's Square</u>:

Alleles    G         g

G           GG       Gg

g           Gg        gg

Offspring:

  • A pumpkin of green seeds GG (25%)
  • Two pumpkins of green heterozygous seeds Gg (50%)
  • One pumpkin of yellow seeds gg (25%)

Genotype proportion 1:2:1

Phenotype proportion 3:1

8 0
3 years ago
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