All categories

2 years ago

PLEASE HELP ME!!!!!!! I don't now how to do this

Mathematics

1 answer:

qwelly [4]2 years ago

8 0

Answer:

Step-by-step explanation:

For example draw something in the room that is rectangular. Like a table or a book. Also, answer the other corresponding questions.

You might be interested in

The sum of the first three terms of geometric sequence is 14. If the first term is 2, find the possible values of the sum of the

Irina18 [472]

Geometric series are in the form of

$a +a*r +a*r^2+...$

Where a is the first term and r is the common ratio .

And it is given that

$2 +2*r +2*r^2=14$

$2r^2+2r-12=0$

$r^2 +r-6=0$

$(r+3)(r-2)=0$

r=-3,2

So the first five terms are

$2+2(-3)+2(-3)^2+2(-3)^3+2(-3)^4 or 2+2(2)+2(2)^2+2(2)^3+2(2)^4$

= 2-6+18-54+162 or 2+4+8+16+32

= 122 or 62

4 0

2 years ago

Read 2 more answers

Simplify using i 3+2i/6+5i

alukav5142 [94]

The answer for your question question is 3+ 16/3 i

5 0

2 years ago

There are 20 machines in a factory. 7 of the machines are defective.

adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

4 0

3 years ago

PLEASE HELP IF YOU ARE GOOD AT ALGEBRA 2 MATH

REY [17]

Answer:I think a is:78.3 since it would be the same and since 0 doesn't have a value.

I think b is: 139.5 because all you are doing is subtracting 287.1-147.6

7 0

2 years ago

A fisherman leaves his home port and heads in the direction N 70 ° W. He travels d1 = 40 mi and reaches Egg Island. The next day

Gnesinka [82]

Answer:

A)82.02 mi

B) 18.7° SE

Step-by-step explanation:

From the image attached, we can see the angles and distance depicted as given in the question. Using parallel angles, we have been able to establish that the internal angle at egg island is 100°.

A) Thus, we can find the distance between the home port and forrest island using law of cosines which is that;

a² = b² + c² - 2bc Cos A

Thus, let the distance between the home port and forrest island be x.

So,

x² = 40² + 65² - 2(40 × 65)cos 100

x² = 1600 + 4225 - (2 × 2600 × -0.1736)

x² = 6727.72

x = √6727.72

x = 82.02 mi

B) To find the bearing from Forrest Island back to his home port, we will make use of law of sines which is that;

A/sinA = b/sinB = c/sinC

82.02/sin 100 = 40/sinθ

Cross multiply to get;

sinθ = (40 × sin 100)/82.02

sin θ = 0.4803

θ = sin^(-1) 0.4803

θ = 28.7°

From the diagram we can see that from parallel angles, 10° is part of the total angle θ.

Thus, the bearing from Forrest Island back to his home port is;

28.7 - 10 = 18.7° SE

4 0

3 years ago