5000(1+.085/4)^n=1000
to find n use log:
1.02125^n
N X log1.02125
when computed=32.9
round to 33 quarters compounded
33/4
equals to 8 years 3 months
Answer:

Step-by-step explanation:
−2|x| < −8 ↷
−2x > 8 −2x < −8
___ __ ___ ___
−2 −2 −2 −2
OR 
Whenever you multiply\divide by a <em>negative</em>, you reverse the inequality symbol.
I am joyous to assist you anytime.
Statisticians use summary measures to describe the amount of variability or spread in a set of data. The most common measures of variability are the range, theinterquartile<span> range (</span>IQR<span>), </span>variance<span>, and standard deviation. This is from google btw</span>
Answer:
89414,89416,89418
Step-by-step explanation:
Let n bet the positive integer and then 2n is an even integer because multiplying n with 2 makes it an even integer.
Now, 2n+2, 2n+4 are the next integers.
Therefore, three consecutive integers are: 2n, 2n+2, 2n+4.
It is given that twice the first integer added to the second is 268,244 that means:




Therefore, three consecutive integers are:
2n=89414, 2n+2=89416, 2n+4=89418
Step-by-step explanation:
∫ dt / (cos²(t) ⁹√(1 + tan(t)))
If u = 1 + tan(t), then du = sec²(t) dt.
∫ du / ⁹√u
∫ u^(-1/9) du
9/8 u^(8/9) + C
9/8 (1 + tan(t))^(8/9) + C