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hichkok12 [17]
3 years ago
12

Sarabeth ran 1 2/5 miles on a path around the park. This was 5/8 of the distance around the park. What is the distance around th

e park.
Mathematics
2 answers:
Citrus2011 [14]3 years ago
5 0
1 + 2/5 = 7 / 5 = 0.2 * 7 = 1.4miles
5/8 = 0.125 * 5 = 0.625 = 62.5% of park distance
1.4 miles = 62.5%
100% / 62.5% = x
total distance / 1.4 = x
total distance = 1.4x

Inga [223]3 years ago
4 0
First, convert 1 2/5 miles to decimal form. That's 1.4 miles. Then convert 5/8 to decimal. That's .625. So, we know that 1.4 miles is .625 of the distance (x) around the park. Here's the equation, and the solution is just division. Easy!

1.4 miles = .625x

1.4/.625 = 2.24 miles
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Which of the values shown are potential roots of f(x) = 3x3 â€"" 13x2 â€"" 3x 45? Select all that apply.
Verdich [7]

The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

And the accurate root is 3 it can be determined by using rules of the rational root equation.

<h2>Given that,</h2>

Function; \rm f(x) = 3x^3 - 13x^2 -3x + 45

<h3>We have to determine,</h3>

Which of the values shown are potential roots of the given equation?

<h3>According to the question,</h3>

Potential roots of the polynomial are all possible roots of f(x).

\rm f(x) = 3x^3 - 13x^2 -3x + 45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

\rm p=\dfrac{All\  the \ positive}{Negative\  factors \ of\  45}

\rm q=\dfrac{All\  the \ positive}{Negative\  factors \ of\  3}

The factor of the term 45 are,

\pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45

And The factor of 3 are,

\pm1, \ \pm3

All the possible roots are,

\dfrac{p}{q} = \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

Now check for all the rational roots which are possible for the given function,

\rm f(x) = 3x^3 - 13x^2 -3x + 45\\\\ f(1) = 3(1)^3 - 13(1)^2 -3(1) + 45 = 3-13-3+45 = 32\neq 0\\\\ f(-1) = 3(-1)^3 - 13(-1)^2 -3(-1) + 45 =- 3-13+3+45 = 32\neq 0\\\\ f(3) = 3(3)^3 - 13(3)^2 -3(3) + 45 = 81-117-9+45 =0\\\\ f(-3) = 3(-3)^3 - 13(-3)^2 -3(-3) + 45 = -81+117+9+45 =-144\neq 0

Therefore, x = 3 is the potential root of the given function.

Hence, The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}.

For more details about Potential roots refer to the link given below.

brainly.com/question/25873992

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2 years ago
A giant pie is created in an attempt to break a world record for baking. The pie is shown below:
Arlecino [84]

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5 0
3 years ago
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4 0
3 years ago
Read 2 more answers
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Brrunno [24]

Hello there!

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3 years ago
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