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3 years ago

-6 + -4y + -11y + 16y = -10 I need the answer A.S.A.P

Mathematics

2 answers:

zubka84 [21]3 years ago

8 0

Answer:

y = -4

Step-by-step explanation:

-6 + -4y + -11y + 16y = -10

Positive negative is negative

-6 - 4y -11y + 16y = -10

-6 - 15y + 16y = -10

-6 + y = -10

Add 6 to both sides to separate the unknown to one side

-6+6 + y = -10 + 6

y = -4

Alja [10]3 years ago

4 0

Answer:

y = -4

Step-by-step explanation:

Step 1 :

Solving a Single Variable Equation :

1.1 Solve : y+4 = 0

Subtract 4 from both sides of the equation :

y = -4

One solution was found :

y = -4

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Please help, I will mark!!

Alik [6]

Answer:

$d=28.28$

Step-by-step explanation:

To calculate the lenght of the diagonal d across the square, we can assume that the square it is compound of two right triangles. So, we can resolve this exercise using The Pythagorean Theorem.

<em>The Pythagorean theorem</em> states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.

If in a right triangle there are legs of length a and b, and the measure of the hypotenuse is c, then the following relation is fulfilled:

$a^{2} +b^{2} =c^{2}$ a is the height, b is the base, and c is

the hypotenuse.

To obtain the value of the hypotenuse

$c= \sqrt{a^{2} +b^{2} }$

To find the value of the lenght of the diagonal d across the square, we have:

$d=\sqrt{a^{2} +b^{2} }$ Where a = b = 20

Substituting the values

$d=\sqrt{(20)^{2} +(20)^{2} }\\d=\sqrt{400+400} =\sqrt{800} \\d=28.284$

Round the answer to 2 decimal places

$d=28.28$

6 0

3 years ago

Find the common difference for the given sequence<br> 1.2, 1.85, 2.5, 3.15, ...

Kay [80]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

What are the points of discontinutity y=(x-3)/x^2-12x+27

madreJ [45]

Answer:

$(3, -\frac{1}{6})$

Step-by-step explanation:

We can rewrite the equation as

$y = \frac{x - 3}{(x - 3)(x - 9)}$

Notice that we have $x - 3$ in both the numerator and the denominator, so it looks like we can divide it out. However, what if $x - 3$ is $0$ ? Then we would have $y = \frac{0}{0 \times (x - 9)} = \frac{0}{0}$ , which is undefined. So although it looks like the numerator and denominator can be simplified, the resulting function we would get from simplification would not have the same behavior as this one (since such a function would be defined for $x = 3$ , but this one is not).

A point of discontinuity refers to a particular point which is included in the simplified function, but which is not included in the original one. In this case, the point which is not included in the unsimplified function is at $x = 3$ . In the simplified version of the function, if we plug in $x = 3$ , we get

$y = \frac{1}{((3) - 9)} = -\frac{1}{6}$

So the point $(3, -\frac{1}{6})$ is our only point of discontinuity.

It's also important to distinguish between specific points of discontinuity and vertical asymptotes. This function also has a vertical asymptote at $x = 9$ (since it causes the denominator to be 0), but the difference in behavior is that in the case of the asymptote, only the denominator becomes 0 for a specific value of $x$