Solve out the actual multiplication problem: 18 x 5 = 90
So you can see that the final answer is 9 tens.
hope that helps :)
Volume =length *breadth *height
Volume =area of the cross section *height
320=area of the cross section * 8
Area of the cross section =320/8
=40cm2
No, you do not have to line up the decimals.
Answer:
<em>Approximate length of the side adjacent to ∠C is </em><em>7.66 inches.</em>
Step-by-step explanation:
*The appropriate triangle is attached below.
From the diagram, the right triangle ABC has
- Hypotenuse =
![\overline{AC}=10\ inch](https://tex.z-dn.net/?f=%5Coverline%7BAC%7D%3D10%5C%20inch)
![m\angle C=40^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20C%3D40%5E%7B%5Ccirc%7D)
The side adjacent to angle C is BC. We can get the length of BC by applying trigonometric operations.
We know that,
![\cos \theta =\dfrac{b}{h}](https://tex.z-dn.net/?f=%5Ccos%20%5Ctheta%20%3D%5Cdfrac%7Bb%7D%7Bh%7D)
Putting the values,
![\Rightarrow \cos 40 =\dfrac{BC}{10}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ccos%2040%20%3D%5Cdfrac%7BBC%7D%7B10%7D)
![\Rightarrow BC=\cos 40 \times {10}](https://tex.z-dn.net/?f=%5CRightarrow%20BC%3D%5Ccos%2040%20%5Ctimes%20%7B10%7D)
![\Rightarrow BC=7.66\ in](https://tex.z-dn.net/?f=%5CRightarrow%20BC%3D7.66%5C%20in)