1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Valentin [98]
3 years ago
11

A rectangular napkin has an area of 88 square centimeters and a length of 8 centimeters.

Mathematics
2 answers:
Volgvan3 years ago
4 0

Answer:

11 cm

Step-by-step explanation:

a= l x w

88= l x 8

88/8= 11

so ll cm is the width of the napkin

Svetllana [295]3 years ago
3 0
11 centimeters
This is because a rectangle has an area of length times width and so you can divide 88 by 8 to get 11
You might be interested in
Celine's Cereal Company is launching a new brand of cereal and she is considering two different sizes for the base of the boxes.
densk [106]

The dimensions of the base of Box 1 are x by 3x.


The base area of Box 1 is:

3x^2

6 0
3 years ago
Read 2 more answers
Madisyn is planting crops in a triangular garden. She is trying to find the amount of fencing
MrRissso [65]

Answer:

Fencing needed = 20.8 units

Step-by-step explanation:

From the figure attached,

Given: Triangle ABC with vertices A(0, 6), B(6, 5) and C(5, -1).

We have to find the length of fence required to cover the triangular garden.

Amount of fencing required = Perimeter of the triangular garden

Perimeter of the garden = AB + BC + AC

Formula to get the distance between A and B,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB = \sqrt{(0-6)^2+(6-5)^2} = \sqrt{37}

BC = \sqrt{(6-5)^2+(5+1)^2} = \sqrt{37}

AC = \sqrt{(0-5)^2+(6+1)^2} = \sqrt{74}

Perimeter = \sqrt{37}+\sqrt{37}+\sqrt{74}

                = 6.08 + 6.08 + 8.60

                = 20.76

                ≈ 20.8 units

Therefore, amount of fencing required to cover the triangular park is 20.8 units.

3 0
2 years ago
PLEASE HELP!! WILL GIVE BRAINLIEST !!!
Ivanshal [37]

Answer:

the outlier is the point at 15

the data is skewed to the bottom because the values below the median are far more spread out; there are more extreme values that are far below the median than above the median.

Step-by-step explanation:

3 0
3 years ago
Find all the solutions of sin x + cos x = 1 in the interval [0, 2pie).
Mashcka [7]

Answer:

X = 0,  π/2 in the interval  [0, 2pi).

Step-by-step explanation:

Use the auxiliary angle method:

R sin(x + a)  = Rsin x cos a + Rcos x sin a = 1

                        sin x         +    cos x             = 1

Comparing coefficients:

R cos a = 1 and R sin a =  1, so

tan a = R sin a / R cos a  = 1

So a = π/4 radians.

Also  R^2(sin^2 a + cos^2 a) =  1^2 + 1^2 = 2

Therefore R = √2.

So √2 sin (x +π/4 = 1

sin x + π/4 = 1/√2

x  + π/4 = π/4

x = 0 radians

Also

x = 0 +  π/2 = π/2.

8 0
2 years ago
HELP I DONT KNOW! I SUCK AT MATH
pogonyaev

Answer:

C

Step-by-step explanation:

5/2=15=6=2.5

6 0
3 years ago
Read 2 more answers
Other questions:
  • What multiplies to give you 108 and adds up to give you -31?
    11·1 answer
  • Your new place needs a 12 ft by 18 ft rug. You notice that these sides are 50% longer than the rug from your old place. What wer
    13·1 answer
  • 19. Represent Real-World Problems The
    14·2 answers
  • Need help fast answer with work shown
    12·1 answer
  • What is the GCF for 24 and 60
    9·1 answer
  • Which Iink between two elements could you remove from the relation so that becomes a function?
    6·1 answer
  • To raise funds, a school sells two kinds of raffle tickets, some for $6 and the rest for $1.50 . Sales for both amounted to $822
    10·2 answers
  • Fifteen percent of the cars in a parking lot are green. If there are 45 green cars, how many cars are there in the parking lot?
    9·1 answer
  • 54 + 38<br> -<br> = (52 +<br> D + 38<br> -<br> =52+ (<br> +38)<br> = 52 +<br> II
    14·1 answer
  • WILL MARK BRAINLIEST PLS HELP. Fill in the table by following the rules provided for each backpack.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!