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REY [17]
3 years ago
9

D=6, Dx=-6, Dy=-24, Dz=-30 what is the solution set

Mathematics
1 answer:
Elis [28]3 years ago
3 0

Answer:

  (x, y, z) = (-1, -4, -5)

Step-by-step explanation:

(x, y, z) = (Dx, Dy, Dz)/D = (-6, -24, -30)/6

(x, y, z) = (-1, -4, -5)

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The tires on your bicycle have a diameter of 20 inches. How many rotations does each tire make when you travel 500 feet?
Art [367]
You take 20 / 12 for the inches in a foot and get 1.6 then times by 500 and get 833.3
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3 years ago
Mr. Falco baked blueberry muffins several times in May using the recipe shown. He used 3 3/4 cups of milk in all. How many times
const2013 [10]

Answer:

use fraction caculator

Step-by-step explanation:

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2 years ago
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Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
3 years ago
An aircraft flew 5 hours with the wind. The return trip took 6 hours against the wind. If the speed of the plane in still air is
Yakvenalex [24]

Answer:

Speed of wind = 23.63 miles per hour

Plane speed in still air = 260 miles per hour

Step-by-step explanation:

Given:

Time taken with wind = 5 hour

Time taken against wind = 6 hour

Assume;

Speed of wind = s

So,

Speed of Plane with wind = (260 + s) miles per hour

Speed of Plane against wind = (260 - s) miles per hour

Distance = speed x time

So,

(260 + s)5 = (260 - s)6

1,300 + 5s = 1,560 - 6s

11s = 260

s = 23.63 miles per hour

Speed of wind = 23.63 miles per hour

Plane speed in still air = 260 miles per hour

5 0
3 years ago
Whats 9 +10 will give brainlest
shtirl [24]

Answer:

19

Step-by-step explanation:

"You stupid"

"No Im not"

"Whats 9+10"

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3 years ago
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