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djyliett [7]
2 years ago
7

Please help, thanks in advance

Mathematics
1 answer:
avanturin [10]2 years ago
3 0

Answer:

D. \frac{45a^{16}c^{34}}{b^{27}}

Step-by-step explanation:

Here you are...

Hope this helps! Brainliest would be much appreciated! Have a great day! :)

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Write two expressions where the solution is 19
marysya [2.9K]
1) 
12+ (26-?) = 19 Find The Missing Value.

2)
x - 5 = 14 What Is The Value Of x ?

Hope This Helps xox
7 0
3 years ago
Read 2 more answers
Please help i’ll give brainliest
Setler79 [48]

Answer:

range

Step-by-step explanation:

*JUST AND EDUCATED GUESS* but id say range

7 0
2 years ago
Point One = (-1,-1)<br> Point Two = (0,4)<br> Point-Slope Form:
-Dominant- [34]

Answer:

y+2=m(x+2)

Step-by-step explanation:

y - y1 = m(x - x1)

y- (-1) = m( x-(-1) )

y+2 = mx +2m

4 0
3 years ago
angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea
atroni [7]

Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

Box:

(56 in)(8 in)(36 in)

Warp paper:

(26 in)(17 in)

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

surface_{1}=(56 in)(8 in)(2)=896 in^{2}

surface_{2}=(8 in)(36 in)(2)=576 in^{2}

surface_{3}=(56 in)(36 in)(2)=4032 in^{2}

surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}

Warp paper:

area=(26 in)(17 in)=442 in^{2}

Dividing the area of the box by the area of the paper:

\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0
3 years ago
56 in²
garri49 [273]

The area of the remaining board is [(L × B) - (l × b)].

According to the statement

We have to find that the area of the remaining board.

So, For this purpose, we know that the

Area of rectangle is the region occupied by a rectangle within its four sides or boundaries. The area of a rectangle depends on its sides.

From the given information:

Suppose the bigger rectangle is labelled as ABCD and the smaller rectangle is labelled as PQRS.

And

Consider that the length and breadth of the bigger rectangle are L and B respectively. And the length and breadth of the bigger rectangle are l and b respectively.

The area of any rectangle is:

Area = Length × Breadth

The area of the bigger rectangle is:

Area of ABCD = L × B

The area of the smaller rectangle is:

Area of PQRS = l × b

Then the area of the remaining board will be:

Area of remaining board = Area of ABCD - Area of PQRS

Area of remaining board= (L × B) - (l × b)

Thus, The area of the remaining board is [(L × B) - (l × b)].

Learn more about Area here

brainly.com/question/8409681

Disclaimer: This question was incomplete. Please find the full content below.

Question:

A rectangle is removed from the middle of a larger rectangular shaped board. What is the area of the remaining board?

#SPJ9

6 0
1 year ago
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