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3 years ago

What is the solution of 10=-15

Mathematics

1 answer:

finlep [7]3 years ago

8 0

The solution would be undefined, since it is not possible for 10 to be equal to -15. Hope this helps! :)

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In the past year and a half, Gnarly the dog lost an average of 2/9 pound each month. Today, Gnarly weighs 14 pounds. How much di

svlad2 [7]

Answer:

Weight before 18 month = 18 pound

Step-by-step explanation:

Given:

Current weight of dog = 14 pound

Weight lose each month = 2/9 pound

Total number of month = $1\frac{1}{2}$ year = 18 month

Find:

Weight before 18 month

Computation:

Total weight lose = Weight lose each month x Total number of month

Total weight lose = 2/9 x 18

Total weight lose = 4 pound

Weight before 18 month = Current weight of dog + Total weight lose

Weight before 18 month = 14 + 4

Weight before 18 month = 18 pound

7 0

3 years ago

Pls answer quick I will give bainlyest to first GOOD answer

Helen [10]

Answer:

R1 - given

R2 - subtraction property of equality

R3 - distribution

S4 - 9x = 61

R5 - division prop. of equality

Step-by-step explanation:

hope this helps :)

5 0

3 years ago

Convert 0:48 to a percent and a simplified fraction

just olya [345]

The answer to this question is 2/5

6 0

3 years ago

Find sin(2x), cos(2x), and tan(2x) from the given information.

larisa86 [58]

Since $\cot(x)=\frac{2}{3}$ and $\cot^{2} x+1=\csc^{2} x$ , we know that:

$\left(\frac{2}{3} \right)^{2}+1=\csc^{2} x\\\\\frac{13}{9}=\csc^{2} x\\\\\csc x=\frac{\sqrt{13}}{3}$

If $\csc x=\frac{\sqrt{13}}{3}$ , this means that $\sin x=\frac{3}{\sqrt{13}}$ and by the Pythagorean identity,

$\sin^{2} x+\cos^{2} x=1\\\left(\frac{3}{\sqrt{13}} \right)^{2}+\cos^{2} x=1\\\frac{9}{13}+\cos^{2} x=1\\\cos^{2} x=\frac{4}13}\\\cos x=\frac{2}{\sqrt{13}}$

Using the double angle formula for sine, $\sin(2x)=2\left(\frac{3}{\sqrt{13}} \right)\left(\frac{2}{\sqrt{13}} \right)=\boxed{\frac{12}{13}}$
Using the double angle formula for cosine, $\cos(2x)=1-2\left(\frac{3}{\sqrt{13}} \right)^{2}=\boxed{-\frac{5}{13}}$
So, since tan=sin/cos, $\tan (2x)=\frac{\sin(2x)}{\cos(2x)}=\frac{\frac{12}{13}}{-\frac{5}{13}}=\boxed{-\frac{12}{5}}$

7 0

2 years ago

The product of two negative integers is 36. The second integer is 5 more than the first. Find the integers.

Finger [1]

-13 -23 because divide by two then add five and subtract 5

8 0

3 years ago