Free takes $20 to the arcade and it costs $2 for every game he plays. Fred needs to leave the arcade with $5.00 to pay for lunch
2 answers:
Answer:
Fred can play maximum of 7 games.
Step-by-step explanation:
Money had with Fred = $20
Cost for each game = $2
Fred needs to leave the arcade with $5.00 to pay for lunch.
Money left with Fred = $20 - $5.00 = $15
Let the number of games be x.
Hence Number of games Fred can play can be calculated as;
Cost for each game multiplied number of games should be less than or equal to Money left with Fred
Hence equation can be framed as;
From above we can say number of games fred can play is 7.5 but number of games cannot be in point hence maximum of 7 games he can play.
Hence Fred can play maximum of 7 games.
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