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3 years ago

1 What is the solution to the equation 5x + 4 =19

Mathematics

1 answer:

ivolga24 [154]3 years ago

5 0

Answer:

x=3

Step-by-step explanation:

5x + 4 = 19

-4 -4

5x = 15

/5 /5

x = 3

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There is a bag filled with 4 blue, 3 red and 5 green marbles.

Vsevolod [243]

<h2>The chances of receiving two greens are 5/31.</h2>

<em>Given a bag containing four blue, three red, and five green marbles, the total result is:</em>

<em>Total number of balls = 4 + 3 + 5 = 12</em>

<em>If green is chosen first, the chances of picking a green are 5/12.</em>

<em>The probability that the second stone is green is 4/11 if it is picked and not replaced (4 greens remaining)</em>

<em>The chance of earning two greens is 5/12 4/11.</em>

<em>The chance of getting two greens is 20/132.</em>

<em>The chance of earning two greens is 5/31.</em>

<h3><em>As a result, the chance of getting two greens is 5/31.</em></h3>

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2 years ago

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UNO [17]

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Step-by-step explanation

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3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.01 \cdot 0.305=0.61$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95$

The 95% confidence interval for the mean is (5.73, 6.95).

4 0

3 years ago

Help i need help with this 10x+16>6x+20

Mamont248 [21]

What does > mean?

10x + 16 ≥ 6x + 20

Subtract both sides by 16

10x ≥ 6x + 4

Subtract both sides by 6x

4x ≥ 4

Divide both sides by 4

x ≥ 1

I believe this is your answer good luck!!

<<<Emily>>>

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3 years ago

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andrey2020 [161]

So what you need to do is find the less he can use.

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3 years ago