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ser-zykov [4K]
3 years ago
14

Write the algebraic expression that matches each graph? PLS HELP I NEED HELP!!!

Mathematics
2 answers:
Vladimir [108]3 years ago
8 0

Looks like y = |x| because the slopes of the lines are both 1

You shift it to the right making it |x-2| and you shift it down making y = -2

combine to get <em>y = |x - 2| - 2</em>.

vlada-n [284]3 years ago
3 0

Answer: -/x/-3

Step-by-step explanation:

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A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)
Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}

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3 years ago
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