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Harlamova29_29 [7]
3 years ago
14

Whats My number is????

Mathematics
2 answers:
Ket [755]3 years ago
5 0
The answer should be 91, 1 is 8 away from the tens digit which is 9!
Blababa [14]3 years ago
5 0

Answer:  The required number is 91.

Step-by-step explanation:  Given that a number has a tens digit that is 8 more than the ones digit. Zero is not one of the digits.

We are to find the number.

Let x and y represents the digit in ten's place and one's place respectively.

So, the number is n=10x+y.

According to the given information, we have

x=8+y.

Therefore,w e get

n=10x+y=10(8+y)+y=80+11y.

Since the number is of two digits and x, y are not zero, so the required value of y is 1.

That is, given number is

n=80+11\times1=91.

Thus, the required number is 91.

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