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rewona [7]
3 years ago
12

Figure ABCD is a parallelogram. If ABCD is also a rhombus, what must be the value of x? 13 15 18 23

Mathematics
2 answers:
Dafna1 [17]3 years ago
8 0

<u>Answer:</u>

x = 13

<u>Step-by-step explanation:</u>

To solve for x in a parallelogram ABCD, which is also a rhombus, one must recall the common properties of parallelogram and rhombus.

One of the properties say that diagonals are perpendicular bisectors of each other, It means that the triangles formed in the figure are right-angles triangle.

Therefore, to calculate the value of x we can write:

<u>(5x - 35) = 90 because it is the right angled triangle.</u>

5x = 90 - 35

5x = 65

x = 65/5

x = 13

nevsk [136]3 years ago
6 0

Answer: First option 13

Solution

If ABCD is a rhombus, the diagonals must be perpendicular, then the angle (5x+25)° must be a right angle (90°):

(5x+25)°=90°

5x+25=90

Solving for x: Subtracting 25 both sides of the equation:

5x+25-25=90-25

Subtracting:

5x=65

Dividing both sides of the equation by 5:

5x/5=65/5

Dividing:

x=13

Answer: The value of x must be 13

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The perimeter of a triangle is 28 feet. One side of the triangle is 5 feet longer than the second side. The third side is 8 feet
Hitman42 [59]

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I'm not sure what trig function to use. Someone please help, and please answer sedulously, and not just for points. Thank you in
Alex Ar [27]

Answer:

w = 6.7451

x = 8.0805

Step-by-step explanation:

Find W

Tan(56) = opposite / adjacent

opposite = 10

Adjacent = w

Tan (56) = 10/w

w*Tan(56) = 10

w = 10 / tan(56)

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Find x

Tan (34) = 10 / (w + x)

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