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3 years ago

13

I need help quickly. I think it's B or D.

2 answers:

Ludmilka [50]3 years ago

5 0

personally id say c cuz the one on the right makes it have no trend, and also because if it was a negative trend there should only have been one answer on it really.

IRINA_888 [86]3 years ago

3 0

B is it the water thing doesn’t make sense because how do you measure “sun”

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Figure PQRS is rotated counterclockwise

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2 years ago

Express the following repeating decimal as a fraction in simplest form.

Ivenika [448]

Answer:

$0.\overline{369} = \frac{41}{111}$

Step-by-step explanation:

x = 0.369369369...

10x = 3.69369369...

100x = 36.9369369...

1000x = 369.369369...

1000x - x = 369

999x = 369

$x = \frac{369}{999} \\\\x = \frac{123}{333}\\\\x = \frac{41}{111}$

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3 years ago

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3 years ago

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vichka [17]

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3 years ago

Find the volume of the solid of revolution generated by revolving the region bounded by y = 2x^2, y = 0, and x = 2 about the x-a

Irina18 [472]

Answer:

$128 \pi/5 units^3$

Step-by-step explanation:

The volume of the solid revolution is expressed as;

$V = \int\limits^2_0 {\pi y^2} \, dx$

Given y = 2x²

y² = (2x²)²

y² = 4x⁴

Substitute into the formula

$V = \int\limits^2_0 {4\pi x^4} \, dx\\V =4\pi \int\limits^2_0 { x^4} \, dx\\V = 4 \pi [\frac{x^5}{5} ]\\$

Substituting the limits

$V = 4 \pi ([\frac{2^5}{5}] - [\frac{0^5}{5}])\\V = 4 \pi ([\frac{32}{5}] - 0)\\V = 128 \pi/5 units^3$

Hence the volume of the solid is $128 \pi/5 units^3$

5 0

2 years ago