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3 years ago

In 2000, the population of Littletown was 17,000.

1 answer:

hjlf3 years ago

7 0

We first must solve for the rate:Rate = 10^[(log[Ending Amount / Beginning Amount] ÷ time)] -1
Rate = 10^[(log(34,000 / 17,000) / 26)] -1Rate = 10^[log(2) / 26] -1Rate = 10^[0.30102999566 / 26] -1Rate = (10^ 0.0115780768) -1
Rate = 1.0270180507-1Rate = .0270180507 

Now for the 2010 population:2010 Amount = 2000 Amount × (1 + rate) time
 2010 Amount =17,000 * (1.0270180507)^10
2010 Amount =17,000 * 1.3055116977 2010 Amount = 22,194

Source 1728.com/expgrwth.htm

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11 more than four times a number is 39

Aliun [14]

Hello!

Your answer is: 7

(X = "A number")

"11 more than four times a number is 39" in equation form is: 4X + 11 = 39

to solve, first subtract 11 from both sides:

4X = 28

then divide both sides by 4 to get:

X = 7

I hope this helps, and have a nice day!

4 0

4 years ago

What are the units for the spring constant, k?

svlad2 [7]

The spring constant, k, in Hooke's Law has units of Newton per meter since it is a constant for the force applied per unit of length. The spring constant measures how strong and stiff the spring is. Hope this answers the question. Have a nice day.

3 0

3 years ago

A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa

BlackZzzverrR [31]

<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

$1/2\times1/2\times1/2\times1/2=1/16$

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have $2^{4}$ or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = $\frac{4!}{2!2!}$ = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = $1/2\times1/2\times1/2\times1/2=1/16$

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = $1/16+1/16+1/16+1/16+1/16=5/16$

6 0

3 years ago

Mark and Julio are selling flower bulbs for a school fundraiser. Customers can buy bags of windflower bulbs and packages of croc

ikadub [295]

Answer:

Bag of windflower bulbs costs $8.50

Package of crocus bulbs costs $17.60

Step-by-step explanation:

Let $x be the price of one bag of windflower bulbs and $y be the price of one package of crocus bulbs.

1. Mark sold 2 bags of windflower bulbs for $2x and 5 packages of crocus bulbs for $5y. In total he earned $(2x+5y) that is $105. So,

2x+5y=105

2. Julio sold 9 bags of windflower bulbs for $9x and 5 packages of crocus bulbs for $5y. In total he earned $(9x+5y) that is $164.50. So,

9x+5y=164.50

3. You get the system of two equations:

$\left\{\begin{array}{l}2x+5y=105\\ \\9x+5y=164.50\end{array}\right.$

From the first equation

$5y=105-2x$

Substitute it into the second equation:

9x+105-2x=164.50

7x=164.50-105

7x=59.5

x=$8.50

So,

5y=105-2·8.5

5y=105-17

5y=88

y=$17.60

5 0

3 years ago

By definition, present value is

MArishka [77]

Answer:

$future \: value \: minus \: interest$

8 0

3 years ago