Solve 64^x = 16^x-1
Please help I need to find what x equals
2 answers:
Answer:
x = -1
Step-by-step explanation:
lhs is 64 to the power of something, while rhs is 16 to the power of something. so x cannot be a positive number.
if you keep x as 0, 64^0 > 16^-1, which means 1 > 1/16. hence x should be lesser than 0.
With -1, 64^-1 = 16^-2, 1/64 = 1/64
Answer:
x= -2
Step-by-step explanation:
64^x = 16^x-1
64= 4^3 and 16=4^2
4^3x = 4^2(x-1)
so we now cancel the 4 from both sides and equate the powers
3x=2(x-1)
3x=2x-2
we now put all the x on one side
3x-2x=-2
x= -2
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<u><em>The correct answer here is d</em></u>
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