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juin [17]
3 years ago
9

If the task is to write firewall specifications for the preparation of a(n) __________, the planner would note that the delivera

ble is a specification document suitable for distribution to vendors.
Computers and Technology
1 answer:
USPshnik [31]3 years ago
3 0

Answer:

RFP

Explanation:

If the task is to write firewall specifications for the preparation of a(n)<u> RFP</u> , the planner would note that the deliverable is a specification document suitable for distribution to vendors.

RFP means request for proposal.

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Develop a C program that calculates the final score and the average score for a student from his/her (1)class participation, (2)
White raven [17]

Answer:

Following are the code to the given question:

#include<iostream>//defining header file

using namespace std;

int main()//defining main method

{

float clspat,test,asst,exam,practice,total,average;//defining floating variable

char name[100];//defining char variable to input value

cout<<"Enter Name of Student: ";//print message

cin>>name; //input value

cout<<"Enter scores in following scoring items between 0 and 100:"<<"\n";//print message

cout<<"Enter class participation score: ";//print message

cin>>clspat;//input value

cout<<"Enter test score: ";//print message

cin>>test;//input value

cout<<"Enter assignment score: ";//print message

cin>>asst;//input value

cout<<"Enter exam score: ";//print message

cin>>exam;//input value

cout<<"Enter practice score: ";//print message

cin>>practice;//input value

total=clspat+test+asst+exam+practice;//calculating total value

average=total/5;//calculating average value

cout<<endl<<"SCORE CARD OF "<<name<<"\n"<<"-----------------------"<<"\n";//print value with message

cout<<"Total score: "<<total<<"\n";//print message with value

cout<<"Average score: "<<average; //print message with value

}

Output:

please find the attached file.

Explanation:

In this code, the floating-point variable is declared, which is used for input value from the user-end and after input the floating-point value it uses the "total, average" variable to calculate its respective values and store its value with init, after storing the value into the variable it uses the print method to print its values.

5 0
3 years ago
Identify a logical operation (along
tankabanditka [31]

Answer: Provided in the explanation section

Explanation:

The Question says;

Identify a logical operation (along

with a corresponding mask) that, when

applied to an input string of 8 bits,

produces an output string of all 0s if and

only if the input string is 10000001.​

The Answer (Explanation):

XOR, exclusive OR only gives 1 when both the bits are different.

So, if we want to have all 0s, and the for input only 10000001, then we have only one operation which satisfies this condition - XOR 10000001. AND

with 00000000 would also give 0,

but it would give 0 with all the inputs, not just 10000001.

Cheers i hope this helped !!

3 0
3 years ago
Digital Subscriber Line (DSL) is the only Internet connection option available for a small office in the middle of nowhere. Whic
andrey2020 [161]

What's up!!! :D A Tech-Savvy here:

Answer:

Symmetric Digital Subscriber Line (SDSL)

Cheers,

Feel free to ask me anything regarding ICT/Tech.

7 0
3 years ago
An organization is using Amazon CloudWatch Logs with agents deployed on its Linux Amazon EC2 instances.
Bumek [7]

Answer:

A and B

Explanation:

EC2 run command gives a management output to review various instances and servers. Here, the logging files, collecting metrics and patches, running script installations can be achieved.

Verify the user permission and the run command, confirms if whether or not the problem of missing logging files is from the settings.

There are several AWS and customer managed policies for cloudwatch logs to give users certain levels for permission. Verifying this determines if there is full access, group logs and creation of group log events, or even a read only access.

4 0
3 years ago
How many different messages can be transmitted in n microseconds using three different signals if one signal requires 1 microsec
SIZIF [17.4K]

Answer:

a_{n} = 2/3 . 2^n + 1/3 . (-1)^n

Explanation:

Let a_{n} represents number of the message that can transmitted in <em>n </em>microsecond using three of different signals.

One signal requires one microsecond for transmittal: a_{n}-1

Another signal requires two microseconds for transmittal: a_{n}-2

The last signal requires two microseconds for transmittal: a_{n}-2

a_{n}= a_{n-1} + a_{n-2} + a_{n-2} = a_{n-1} + 2a_{n-2}, n ≥  2

In 0 microseconds. exactly 1 message can be sent: the empty message.

a_{0}= 1

In 1 microsecond. exactly 1 message can be sent (using the one signal of one  microseconds:

a_{0}= 1

2- Roots Characteristic equation

Let a_{n} = r^2, a_{n-1}=r and a_{n-2}= 1

r^2 = r+2

r^2 - r - 2 =0                 Subtract r+6 from each side

(r - 2)(n+1)=0                  Factorize

r - 2 = 0 or r +1 = 0       Zero product property

r = 2 or r = -1                 Solve each equation

Solution recurrence relation

The solution of the recurrence relation is then of the form a_{1} = a_{1 r^n 1} + a_{2 r^n 2} with r_{1} and r_{2} the roots of the characteristic equation.

a_{n} =a_{1} . 2^n + a_{2}.(-1)"

Initial conditions :

1 = a_{0} = a_{1} + a_{2}

1 = a_{1} = 2a_{1} - a_{2}

Add the previous two equations

2 = 3a_{1}

2/3 = a_{1}

Determine a_{2} from 1 = a_{1} + a_{2} and a_{1} = 2/3

a_{2} = 1 - a_{1} = 1 - 2 / 3 = 1/3

Thus, the solution of recursion relation is a_{n} = 2/3 . 2^n + 1/3 . (-1)^n

6 0
3 years ago
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