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3 years ago

8

Joshua payed $1.99 for a pack of gum that contains 5 pieces of gum.Joshua has 110 pieces of gum. How much money did he pay for a

ll his gum?

1 answer:

IgorLugansk [536]3 years ago

8 0

Joshua pays 43.78 because he buys 22 packs. I found this by 110/5 . Then I multiplied 1.99 by 22 and got the final answer $43.78

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Please, help me on this question, guys! I know the answer for (a) so I'll write down, too. For (b) I tried "$89,000 because that

Alexeev081 [22]

Let x be a random variable representing the price of a Congo-imported black diamond. Let the higher price be p. Then,
P(x < p) = P(x < (p - mean)/sd) = P(x < (p - 60,430)/21,958.08) = P(z < 2)
Therefore,
(p - 60,430)/21,958.08 = 2
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p = 34,916.16 + 60,430 = 104.346.16

Therefore, The required price is $104,346.16

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3 years ago

Solve the simultaneous equation <br> 2x-5y=9<br> 3x+4y=2

Dmitriy789 [7]

Answer/Step-by-step explanation:

2x-5y=9

Add 5y to both sides of the equation.

2x=9+5y

Divide each term by 2 and simplify.

Divide each term in 2x=9+5y by 2

$\frac{2x}{2} =\frac{9}{2} +\frac{5y}{2}$

Cancel the common factor of 2.

Divide x by 1.

$x=\frac{9}{2} +\frac{5y}{2}$

$y=\frac{-9}{5} +\frac{2x}{5}$

----------------------------------------------------------------------------------------------------------------

3x+4y=2

Add 4y to both sides of the equation

3x=2+4y

Divide each term by 3 and simplify.

Divide each term in 3x=2+4y by 3.

$\frac{3x}{3} =\frac{2}{3} +\frac{4y}{3}$

Cancel the common factor of 3.

Divide x by 1.

$x=\frac{2}{3} +\frac{4y}{3}$

$y=\frac{-1}{2} +\frac{3x}{4}$

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The leg of a right triangle is 3 units and the hypotenuse is 11 units. What is the length, in units, of the other leg of the tri

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Answer:

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Step-by-step explanation:

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Answer:

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