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Otrada [13]
3 years ago
14

anna wants to finish a 26.2 mile race in 5 hours. If she runs the first 3 hours of the race at a speed of 6 miles per hour, what

must her speed be for the rest of the race
Mathematics
1 answer:
Oxana [17]3 years ago
3 0
First off you need to multiply 6 by 3 for how many miles she went and then divide the leftover total by two (For the last two hours) to realize she needs to run 4.1 mph.

Hope this helped :)
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Mr. Sanchez’s class sold fruit pies for $1.55 each and Mr. Kelly’s class sold bottles of fruit juice for $1.40 each. Together, t
hoa [83]

Answer:

Mr. Sanchez's class sold 28 fruit pies and Mr. Kelly's class sold 32 bottles of fruit juice.

Step-by-step explanation:

Let x be the number of fruit pies sold and y be the number of bottles of fruit juice sold.

Together, the classes sold 60 items, so

x + y = 60

Mr. Sanchez’s class sold fruit pies for $1.55 each, so x fruit pies cost $1.55x.

Mr. Kelly’s class sold bottles of fruit juice for $1.40 each, so y bottles of fruit juice cost $1.40y.

Together, the classes  earned $88.20 for their school, so

1.55x + 1.40y = 88.20.

You get the system of two equations:

\left\{\begin{array}{l}x+y=60\\ \\1.55x+1.40y=88.20\end{array}\right.

From the first equation:

x=60-y

Substitute it into the second equation:

1.55(60-y)+1.40y=88.20\\ \\93-1.55y+1.4y=88.2\\ \\-0.15y=88.2-93\\ \\-0.15y=-4.8\\ \\0.15y=4.8\\ \\15y=480\\ \\y=32\\ \\x=60-32=28

Mr. Sanchez's class sold 28 fruit pies and Mr. Kelly's class sold 32 bottles of fruit juice.

8 0
3 years ago
Which is the equation of a hyperbola with directrices at y = ±2 and foci at (0, 4) and (0, −4)?
Advocard [28]

Answer:

Step-by-step explanation:

First off, I'm assuming that when you said "directrices" you mean the oblique asymptotes, since hyperbolas do not have directrices they have oblique asymptotes.

If we plot the asymptotes and the foci, we see that where the asymptotes cross is at the origin. This means that the center of the hyperbola is (0, 0), which is important to know.

After we plot the foci, we see that they are one the y-axis, which is a vertical axis, which means that the hyperbola opens up and down instead of sideways. Knowing those 2 characteristics, we can determine that the equation we are trying to fill in has the standard form

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1

We know h and k from the center, now we need to find a and b. Those values can be found from the asymptotes. The asymptotes have the standard form

y = ±\frac{a}{b}(x-h)+k

Filling in our asymptotes as they were given to us:

y = ±\frac{2}{1}(x-0)+0 where a is 2 and b is 1. Now we can write the formula for the hyperbola!:

\frac{(y-0)^2}{4}-\frac{(x-0)^2}{1}=1 which of course simplifies to

\frac{y^2}{4}-\frac{x^2}{1}=1

4 0
4 years ago
Double the sum of 13 and a number
Alla [95]
The answer is: 2(13+x)
6 0
4 years ago
Will give brainliest <br> The question is on the picture
lora16 [44]

Answer:

umm 1 2 3 4

Step-by-step explanation:

6 0
3 years ago
Answer soon please and thank you! (3,-6) is an endpoint coordinate on a line segment, where the midpoint is given to us as (1, -
Papessa [141]

Answer:

  C.  (-1, 2)

Step-by-step explanation:

The midpoint has coordinates that are the average of the endpoint coordinates. If the endpoints are A and B, and the midpoint is M, the equation for this is ...

  M = (A+B)/2

Solving for B, we get ...

  2M = A + B

  2M - A = B

This tells us we can find the other endpoint by subtracting the coordinates of the given endpoint from twice the midpoint coordinates. (It is useful to remember this.)

  B = 2(1, -2) - (3, -6) = (2-3, 2(-2)-(-6)) = (-1, 2)

The other endpoint is (-1, 2).

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You can also graph the points and find one as far from center as the given endpoint is.

3 0
4 years ago
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