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olchik [2.2K]
3 years ago
13

Sasha solved an equation, as shown below: Step 1: 8x = 56 Step 2: x = 56 – 8 Step 3: x = 48 Part A: Is Sasha's solution correct

or incorrect? If the solution is incorrect, explain why it is incorrect and show the correct steps to solve the equation. (6 points) Part B: How many solutions does this equation have? (4 points)
Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0
Incorrect, she should have divided both sides by 8. The answer should be x=7. There is only 1 solution to the equation because x is raised to the first degree. It is not a polynomial equation so there won't be more than 1 answer to the equation.
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babymother [125]

The second one, fourth one, and sixth one are true.

Hope this helps!

8 0
3 years ago
Enter an equation of the form y= mx for the line that passes through the
hammer [34]

Answer:

y = 13x

Step-by-step explanation:

gradient = 13

x = 0

y = 0

\frac{Δy}{Δx}

so  \frac{y - 0}{x - 0} = 13

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y = 13x

5 0
3 years ago
Damon is 7 years older than his brother Mark. The sum of Damon and marks age is 29
Ugo [173]

Answer:

Damon is 18, Damon's brother is 11 years old.

Step-by-step explanation:

So, the total age of them both is 29. Damon is 7 years older, so we use 29-7=22. Now, 22 is Damon's brother's age times 2, so we use 22/2=11. 11 is Damon's age is 11+7=18, and His brothers age is 11.

3 0
3 years ago
Read 2 more answers
What are the solutions of x² + 6x - 16 = 0?
AveGali [126]

Step-by-step explanation:

x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}}{2\cdot \:1}\\\sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}\\\sqrt{6^2+64}\\\sqrt{36+64}\\\sqrt{100}\\\sqrt{10^2}\\=10\\x_1=\frac{-6+10}{2\cdot \:1},\:x_2=\frac{-6-10}{2\cdot \:1}\\\\\bold{x_1:2}\\\frac{-6+10}{2\cdot \:1}\\\frac{4}{2\cdot \:1}\\\frac{4}{2}\\=2\\\\\bold{x_2:-8}\\\frac{-6-10}{2\cdot \:1}\\\frac{-16}{2\cdot \:1}\\\frac{-16}{2}\\-\frac{16}{2}\\=-8

Answer:

x₁ = 2

x₂ = -8

6 0
9 months ago
What are the challenges of similar triangles?
Lady bird [3.3K]

Answer:

There are two types of similar triangle problems; these are problems that require you to prove whether a given set of triangles are similar and those that require you to calculate the missing angles and side lengths of similar triangles. Subtract both sides by 130°. Hence; By Angle-Angle (AA) rule, ΔPQR~ΔXYZ.

Step-by-step explanation:

6 0
2 years ago
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