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olchik [2.2K]
4 years ago
13

Sasha solved an equation, as shown below: Step 1: 8x = 56 Step 2: x = 56 – 8 Step 3: x = 48 Part A: Is Sasha's solution correct

or incorrect? If the solution is incorrect, explain why it is incorrect and show the correct steps to solve the equation. (6 points) Part B: How many solutions does this equation have? (4 points)
Mathematics
1 answer:
bekas [8.4K]4 years ago
4 0
Incorrect, she should have divided both sides by 8. The answer should be x=7. There is only 1 solution to the equation because x is raised to the first degree. It is not a polynomial equation so there won't be more than 1 answer to the equation.
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Divide (3x^3 + x2 – 4) by (x + 2).
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Answer:

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Step-by-step explanation:

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2 years ago
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In a large data set the 40th percentile is 125 and the 82nd percentile is 158. Approximately what percentage of observations lie
liq [111]

Answer:

42% of observations lie between 125 and 158.

Step-by-step explanation:

Interpretation of a percentile

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

Two values have a percentile, how many are between then?

In this example, y is larger than x.

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

When a value Z is said to be in the yth percentile of a set, y% of the values in the set are lower than V and (100-y)% of the values in the set are higher than V.

Also, (y-x)% of the values are between V and Z.

In this problem, we have that:

125 is the 40th percentile

158 is the 82nd percentile

Approximately what percentage of observations lie between 125 and 158

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3 0
3 years ago
Solve: 2 ( x-2 ) = 6
Umnica [9.8K]
<span>2 ( x-2 ) = 6
Use distributive property.
2x - 4 = 6
Add 4 to both sides
2x = 10
Divide 2 on both sides so that the only thing remaining on the left side is the variable x.
Final Answer: x = 5</span>
3 0
3 years ago
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