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KonstantinChe [14]
4 years ago
15

424×3 write a matching expression

Mathematics
1 answer:
irinina [24]4 years ago
6 0

Answer: 1272/3

Step-by-step explanation:

424*3=1272

so another way to write this to match this expression is to use the same nuimbers but in a different form so division in one 1272/3=424

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Michelle and Mitchell are making friendship bracelets to sell at a craft fair. Michelle can make 35 bracelets in 7 hours, and Mi
NeTakaya

Answer:Mitchell can make more bracelets

Step-by-step explanation:

  • Michelle does 35 in 7 hours 35÷7=5
  • Mitchell does 16 in 2 hours 16÷2=8
  • So Mitchell makes more bracelets in 1 hour.
5 0
4 years ago
Justin is starting his own laundry business. He charges $15.10 per hour. If he knows he will work 200 hours per month, how much
KiRa [710]
15.10 hours times 200 hours equals 3,020
3 0
3 years ago
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If you drive your car for 3 hours at an average speed of 130 km per hour. How far did you go?
AlexFokin [52]

Answer:390

Step-by-step explanation:130x3=390

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3 years ago
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HELP PLZZ will give brainliest <3
melisa1 [442]

Answer:

0

1

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

\dfrac{a}{\sin A} = \dfrac{b}{\sin B}

\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}

\dfrac{1}{0.5} = \dfrac{4}{\sin B}

\sin B = 2

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

\dfrac{b}{\sin B} = \dfrac{c}{\sin C}

\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}

\sin C = \dfrac{8.9\sin 63^\circ}{10}

C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}

C \approx 52.5^\circ

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0
4 years ago
Gregory knows that ABC is reflected onto ABC which statement about the figure is true
AVprozaik [17]

Answer:

Option a is right

Step-by-step explanation:

Given that a triangle ABC is reflected in triangle A'B'C'

Here reflection is done on a line

If you imagine the line as a mirror then ABC will have image on the mirror line as A'B'C'

Recall that in a mirror the object and image would be equidistant from the mirror and also the line joining the image and object would be perpendicular to the mirror

But note that corresponding images will only be perpendicular bisector to the line of reflection,

So A and A' only will be corresponding so AA' will have mid point on line

Option 1 is right

4 0
4 years ago
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