Question

In △ABC, AB = BC = 20 and DE ≈ 9.28. Approximate BD.

Answer 1

Answer:

BD = 5

Step-by-step explanation:

∠A = 60°

Since AB = 20 = BC, Then ∠B = 60° resulting in a equilateral triangle with ∠C = 60°.  Then dividing ∠DAE into half gives 4 = angles of 15° yielding each secition of BC being equal to 20/4 = 5.  Do i don't think DE ≈ 9.28 cannot occur.